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α
r
= Λ cos Φ 0
,
π/ 2 −Φ 0
R ( π/ 2
(17.14)
Φ )
cos Λ cos Φ 0
π/ 2 −Φ 0
x
y
= R ( π
sin Λ cos Φ 0
,
2
Φ )
(17.15)
π/ 2
Φ 0
Λ 1 = cos Φ
π/ 2 Φ 0
π/ 2 − Φ , Λ 2 =1 .
(17.16)
cos Φ 0
Fig. 17.6. Mapping the sphere to a cone. Polar aspect, equidistant mapping of the set of meridians, equidistant
and conformal on the standard parallel Φ = Φ 0 =30 , point-like North Pole
17-213 Equidistance and Conformality on Two Parallels (Secant Cone, J.N. de L'Isle
1688-1768), Compare with Fig. 17.7
If instead of one parallel two parallel circles are required to be mapped equidistantly, this approach
leads to a secant cone, the so-called de L'Isle projection , named after the French astronomer
Joseph Nicolas de L'Isle. We start from ( 17.7 ) and demand that ( 17.17 ) is satisfied for the two
parallel circles Φ = Φ 1 and Φ = Φ 2 . We obviously receive two equations for the two unknowns
n := sin Φ 0 (cone constant!) and c , the result of which is ( 17.18 ). We end up with the mapping
equations ( 17.19 )or( 17.20 ) with the left principal stretches ( 17.21 ). For Φ = Φ 1 or Φ = Φ 2 ,we
even experience conformality (isometry), Λ 1 = Λ 2 =1.
Λ 1 | Φ = Φ 1 = n R 2
Φ 1 + c
R cos Φ 1
= Λ 1 | Φ = Φ 2 = n R 2
Φ 2 + c
R cos Φ 2
=1 ,
(17.17)
 
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