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=
=
29
λ 9
9 0
26
λ 3
3 3
=
=
(1.34)
λ
λ
= λ 2
= λ 2
79 λ + 1369 =
79 λ + 1369 =
=0 ,
=0 ,
I := tr[JJ ] = tr[J J] = 79 ,
II := det[JJ ]=det[J J] = 1369 ,
(1.35)
1 = λ 1 =7 . 302 692 ,
λ 1 =53 . 329 317 ,
(1.36)
2 = λ 2 =5 . 066 624 .
λ 2 =25 . 670 683 ,
The left eigenspace is spanned by the left eigencolumns ( u 1 , u 2 ), the right eigenspace by the
right eigencolumns ( v 1 , v 2 ), namely
(JJ
(J J
λ 1 I 2 ) u 1 = 0 ,
λ 1 I 2 ) v 1 = 0 ,
(1.37)
(JJ − λ 2 I 2 ) u 2 = 0 ,
(J J − λ 2 I 2 ) v 2 = 0 ,
or
u 11
u 21
= 0 ,
v 11
v 21
= 0 ,
24 . 329 317
9
27 . 329 317
3
9
3 . 329317
3
0 . 329 317
(1.38)
3 . 329 317 9
9 . 329 317
u 12
u 22
= 0 ,
0 . 329 317 3
3 . 329 317
v 12
v 22
= 0 .
Note that the matrices JJ
λ I 2 and J J
λ I 2 have only rank one. Accordingly, in order to solve
the homogenous linear equations uniquely, we need an additional constraint. Conventionally, this
problem is solved by postulating normalized eigencolumns ,namely
u 11 + u 21 =1 ,u 12 + u 22 =1 , 11 + v 21 =1 ,v 12 + v 22 =1 ,
(1.39)
u 1 = u 2 =1 ,
v 1 = v 2 =1 .
The left eigencolumns, which are here denoted as ( u 1 , u 2 ), are constructed from the following
system of equations:
24 . 329 317 u 11 +9 u 21 =0 ,
+3 . 329 317 u 12 +9 u 22 =0 ,
(1.40)
u 11 + u 21 =1 ,
12 + u 22 =1 .
This system of equations leads to two solutions. In the frame of the example to bc considered
here, we have chosen the following result:
u 11 =+0 . 346 946 , u 12 =+0 . 937 885 ,
(1.41)
u 21 =+0 . 937 885 , u 22 =
0 . 346 946 .
 
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