Geography Reference
In-Depth Information
Case 3
(normal equiareal cylindric mapping, equidistant on the equator):
Φ
B
A
+
B
(
A
+
B
cos
Φ
)d
Φ
=
f
(
Φ
)=
0
Φ
Φ
B
2
A
+
B
B
2
A
+
B
sin
Φ.
AB
A
+
B
AB
A
+
B
Φ
+
d
Φ
+
d
Φ
cos
Φ
=
=
(14.69)
0
0
Mapping equations and principal stretches:
x
y
=
, Λ
1
=
F
(0)
(
A
+
B
)
Λ
A
+
B
A
+
B
cos
Φ
,
F
(
Φ
)
=
B
2
AB
A
+
B
Φ
+
A
+
B
sin
Φ
Λ
1
=
A
+
B
cos
Φ
1
Λ
2
=
.
(14.70)
A
+
B
Let us now “switch” from the polar aspect of the mapping “ellipsoid-of-revolution to cylinder”
to the transverse aspect of the mapping “ellipsoid-of-revolution to cylinder”.
Search WWH ::
Custom Search