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= cos Φ 0
1 2
( Λ 1
1) 2 +( Λ 2
1) 2
cos Φ
2
1
cos 2 Φ (cos 2 Φ 0 2cos Φ cos Φ 0 +cos 2 Φ ) ,
=
(10.19)
Φ
1
sin Φ
1
cos Φ
d Φ
(cos 2 Φ 0
2cos Φ cos Φ 0 +cos 2 Φ )
I A (conformal) =
0
(10.20)
cos 2 Φ 0 ln tan π
2 Φ cos Φ 0 +sin Φ .
1
sin Φ
4 + Φ
=
2
Auxiliary integrals:
cos Φ =lntan π
= 1
d Φ
4 + Φ
2 ln 1+sin Φ
1 sin Φ ,
(10.21)
2
d Φ = Φ,
(10.22)
d Φ cos Φ =sin Φ.
In order to determine the unknown parameter Φ 0 , we restrict the Airy distortion energy integral
to the region between Φ =
85 .
±
I A (conformal) = min
(10.23)
d I A / d Φ 0 =0 ,
2sin Φ 0 cos Φ 0 ln tan π
+2 Φ sin Φ 0 =0 ,
4 + Φ
2
sin Φ 0
= 0
(10.24)
Φ
ln tan ( 4 + 2 ) ,
cos Φ 0 =
(10.25)
Φ =85 ,
Φ 0
=61 . 72 , I A =0 . 5426 .
(10.26)
End of Proof.
 
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