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=
cos
Φ
0
1
2
(
Λ
1
−
1)
2
+(
Λ
2
−
1)
2
cos
Φ
−
2
1
cos
2
Φ
(cos
2
Φ
0
−
2cos
Φ
cos
Φ
0
+cos
2
Φ
)
,
=
(10.19)
Φ
1
sin
Φ
1
cos
Φ
∗
d
Φ
∗
(cos
2
Φ
0
2cos
Φ
∗
cos
Φ
0
+cos
2
Φ
∗
)
I
A
(conformal) =
−
0
(10.20)
cos
2
Φ
0
ln tan
π
2
Φ
cos
Φ
0
+sin
Φ
.
1
sin
Φ
4
+
Φ
=
−
2
Auxiliary integrals:
cos
Φ
=lntan
π
=
1
d
Φ
4
+
Φ
2
ln
1+sin
Φ
1
−
sin
Φ
,
(10.21)
2
d
Φ
=
Φ,
(10.22)
d
Φ
cos
Φ
=sin
Φ.
In order to determine the unknown parameter
Φ
0
, we restrict the Airy distortion energy integral
to the region between
Φ
=
85
◦
.
±
I
A
(conformal) = min
⇔
(10.23)
d
I
A
/
d
Φ
0
=0
,
2sin
Φ
0
cos
Φ
0
ln tan
π
+2
Φ
sin
Φ
0
=0
,
4
+
Φ
−
2
sin
Φ
0
= 0
(10.24)
⇒
Φ
ln tan (
4
+
2
)
,
cos
Φ
0
=
(10.25)
Φ
=85
◦
,
Φ
0
=61
.
72
◦
,
I
A
=0
.
5426
.
(10.26)
End of Proof.
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