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1
−
,
1
cos
2
φ
1
a
sin
φ
sin
Φ −
1
a
cos
φ
cos
Φ
d
Φ
=
−
d
φ
d
2
ln
Λ
d
φ
2
(
φ
0
,Φ
0
) = 0
(9.58)
⇒
1
−
E
2
sin
2
Φ
0
1
a
cos
φ
0
=
cos
Φ
0
.
−
E
2
End of Proof.
Proof (lemma relations).
Intermediate results:
r
=
N
0
cos
Φ
0
a
cos
φ
0
,
(9.59)
a
sin
φ
0
=sin
Φ
0
,
(9.60)
1
−
E
2
sin
2
Φ
0
1
cos
Φ
0
=
N
0
a
cos
φ
0
=
a
1
sin
2
φ
0
=
−
M
0
cos
Φ
0
.
(9.61)
−
E
2
Action item: combine (
9.59
)and(
9.61
) and find
A
1
√
1
1
− E
2
sin
2
Φ
0
=
M
0
N
0
.
r
=
A
1
cos
Φ
0
a
cos
φ
0
1
−
E
2
1
=
(9.62)
E
2
sin
2
Φ
0
−
Action item: combine (
9.60
)and(
9.61
) and find
1
− E
2
sin
2
Φ
0
tan
Φ
0
=
M
0
1
−
E
2
tan
φ
0
=
N
0
tan
Φ
0
.
(9.63)
Action item: combine (
9.60
)and(
9.61
) and find
a
=
sin
2
Φ
0
+
N
0
M
0
cos
2
Φ
0
=cos
Φ
0
N
0
M
0
tan
2
Φ
0
.
(9.64)
(If
N
0
/M
0
=1
,
then
a
=1
.
)
Solve the mapping equations at the initial fundamental point
P
0
(
Λ
0
,Φ
0
) with respect to the
integration constant
c
and find
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