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sin
Φ
1+cos
Φ
sin(
Λ − Ω
)
1
−
cos
Φ
sin(
Λ − Ω
)
.
(ii) Meta-eta-latitude:
sin
B
=
=
−
cos
Φ
sin(
Λ
−
Ω
)
.
(3.84)
(iii) Substitutions:
1
√
1+tan
2
A
,
sin
A
=
tan
A
√
1+tan
2
A
,
cos
A
=
Ω
)
cos
2
(
Λ − Ω
)+tan
2
Φ
,
sin
A
=
cos(
Λ
−
tan
Φ
cos
2
(
Λ − Ω
)+tan
2
Φ
,
cos
A
=
(3.85)
1
cos
B
=
1
1
cos
2
Φ
sin
2
(
Λ
−
−
Ω
)
1
1
Ω
)
1
=
Ω
)
.
−
cos
Φ
sin(
Λ
−
−
cos
Φ
sin(
Λ
−
Box 3.17 (The backward problem of transforming spherical frames of reference: the transverse
aspect. Input variables:
A, B, Ω, I
=
π/
2. Output variables:
Λ, Φ
).
(i) Longitude:
tan
B
cos
A
.
tan(
Λ − Ω
)=
−
(3.86)
(ii) Latitude:
sin
Φ
=cos
B
sin
A.
(3.87)
(iii) Substitutions:
sin
B
cos
Φ
,
sin(
Λ
−
Ω
)=
−
Ω
)=+
tan
Φ
cos(
Λ
−
tan
A
,
(3.88)
sin
B
sin
Φ
sin
A
cos
A
=
−
tan
B
cos
A
.
tan(
Λ − Ω
)=
−
3-34 The Transverse Frame of Reference of the Sphere: Part Two
The transverse case is a special case of an oblique frame of reference. Since it has gained great
interest in map projections, we devote another special section to the transverse aspect. In short,
for such a peculiar aspect, the meta-North Pole is chosen to be located in the conventional equator
of the reference sphere
r
. In short, the spherical latitude
φ
0
=0
◦
of the meta-North Pole is fixed
to zero. Accordingly, we specialize the forward and backward transformation formulae according
S
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