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sin Φ
1+cos Φ sin( Λ − Ω ) 1 cos Φ sin( Λ − Ω ) .
(ii) Meta-eta-latitude:
sin B =
=
cos Φ sin( Λ
Ω ) .
(3.84)
(iii) Substitutions:
1
1+tan 2 A , sin A =
tan A
1+tan 2 A ,
cos A =
Ω )
cos 2 ( Λ − Ω )+tan 2 Φ , sin A =
cos( Λ
tan Φ
cos 2 ( Λ − Ω )+tan 2 Φ ,
cos A =
(3.85)
1
cos B =
1
1
cos 2 Φ sin 2 ( Λ
Ω )
1
1
Ω ) 1
=
Ω ) .
cos Φ sin( Λ
cos Φ sin( Λ
Box 3.17 (The backward problem of transforming spherical frames of reference: the transverse
aspect. Input variables: A, B, Ω, I = π/ 2. Output variables: Λ, Φ ).
(i) Longitude:
tan B
cos A .
tan( Λ − Ω )=
(3.86)
(ii) Latitude:
sin Φ =cos B sin A.
(3.87)
(iii) Substitutions:
sin B
cos Φ ,
sin( Λ
Ω )=
Ω )=+ tan Φ
cos( Λ
tan A ,
(3.88)
sin B
sin Φ
sin A
cos A =
tan B
cos A .
tan( Λ − Ω )=
3-34 The Transverse Frame of Reference of the Sphere: Part Two
The transverse case is a special case of an oblique frame of reference. Since it has gained great
interest in map projections, we devote another special section to the transverse aspect. In short,
for such a peculiar aspect, the meta-North Pole is chosen to be located in the conventional equator
of the reference sphere
r . In short, the spherical latitude φ 0 =0 of the meta-North Pole is fixed
to zero. Accordingly, we specialize the forward and backward transformation formulae according
S
 
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