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Box 1.53 (Reference frames (3-leg) of type Gauss, Cartan, and Darboux).
1
l
2
The left manifolds (
M
M
l ,G 12 =0) .
Cartan :
C 1 :=
Darboux :
D 1 ;= X = d d S ,
D 2 ;= D 3
Gauss :
G 1 := X ( U,V )
G 1
G 1
G 1
G 11
=
,
∂U ,
G 2 := X ( U,V )
G 2
G 2
G 2
C 2 :=
=
,
×
D 1 =
(1.322)
G 22
,
=
D 1 ) ,
D 3 = C 3 = G 3 .
( D 3
∂V
C 3 := C 1
×
C 2 =
G 1 × G 2
G 1 × G 2
G 3 :=
.
=
( C 1
C 2 )= G 3 .
The right manifolds ( c 12 =0) .
Cartan :
c 1 :=
Darboux :
d 1 := x = d x ( u ( s ) ,v (6))
Gauss :
g 1 := x ( u ( U ) ,v ( V ))
g 1
g 1
,
,
,
d s
g 2
∂U
c 2 :=
,
c 3 := c 1 × c 2 =
= ( c 1 c 2 ) .
d 2 := d 3 × d 1 =
= ( d 3 ∧ d 1 ) ,
d 3 = c 3 = g 3 .
(1.323)
g 2 := x ( u ( U ) ,v ( V ))
,
g
2
∂V
g 1 × g 2
g 1 × g 2
g 3 :=
.
Those forms of reference are needed to represent cos Ψ l and cos Ψ r , the cosine of the angles between
the tangent vector C 1 and c 1 , respectively, and the tangent vector D 1 and d 1 , respectively
(also called “Cartan 1” and “Darboux 1”) by means of the scalar product
X |
x |
C 1
and
c 1
,
respectivel y. S econd, according to Bo x 1 .54 ,wederiveth eb asicrelationscos Ψ l = G 11 U and
sin Ψ l = G 22 V as well as cos Ψ r = g 11 u and sin Ψ r = g 22 v .
U ,V }
u ,v }
express the
derivative of the parameterized curve C ( S )and c ( s ), respectively, with respect to the canonical
curve parameters
{
and
{
. Third, outlined in Box 1.55 , by means of the chain
rule, we succeed to derive {U ,V } and {u ,v } , respectively, in terms of the elements of the
Jacobi matrices [
{
arc length S , arc length s
}
] and the stretches d s/ dS and d S/ ds,
respectively. In this way, we succeed to represent cos Ψ l and sin Ψ l and cos Ψ r and sin Ψ r in terms
of the elements of the left and the right Cauchy-Green matrix C l and C r , respectively. Fourth,
{
U, V
}
/∂
{
u, v
}
]and[
{
u,v
}
/∂
{
U, V
}
Box 1.56 leads us to the left and the right angular shear, l and r , respectively. Our great
results are presented in Corollary 1.21 . The proof follows the lines of Box 1.56 ,namelythe addition
theorem tan( x−y ) = (tan x +tan y ) / (1+ tan x tan y ). tan l ( Ψ l )aswellastan r ( Ψ r ) establish
the optimization criteria for maximal angular distortion . Fifth, the characteristic optimization
problem l ( ψ l ) = extr. or r ( ψ r ) = extr. is dealt with in Box 1.57 . Indeed, we find the two
stationary points tan Ψ l md tan Ψ r . These stationary solutions lead us to the extremal values of
l and r . The celebrated representations
sin l
sin r =
Λ 1
Λ 2
Λ 1 + Λ 2
λ 1
λ 2
λ 1 + λ 2
=
±
versus
±
(1.324)
From these extremal values of left and right angular shear l and r , we derive the left and
right maximal angular distortion Ω l and Ω r , respectively, namely
Ω l =2arcsin
versus Ω r =2arcsin
Λ 1
Λ 2
Λ 1 + Λ 2
λ 1
λ 2
λ 1 + λ 2
(1.325)
based upon the symmetry l =
r and Ω l := l l , Ω r := r r .
Indeed, Ω l and Ω r are the maximal data of angular distortion.
l , r =
 
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