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connecting ship and sonar is wrapped around the drum, whose maximum angular
velocity
ω
is calculated according to this formula described by [
14
]:
v
r
b
¼
2
33
1
s
x ¼
15
¼
13
:
ð
5
Þ
:
0
x—
radius of the cable drum, m. The rpm
of the drum is calculated according to this formula:
the cable drum angular velocity, 1/s, r
b
30
x
p
n
¼
¼
127
:
36 aps
=
min
ð
6
Þ
The moment of the inertia of the load:
¼
90
¼
2
:
02 kgm
2
J
m
¼
m
v
2
2
2
13
max
x
:
ð
7
Þ
2
:
33
2
The coef
cient of reduction for cable drum is described (
8
):
n
mo
n
i
¼
20
ð
8
Þ
i
—
the reduction coef
cient, n
mot
—
the cable drum motor rpm. The torque that is
needed to lift the weight (
9
):
M
s
¼
mgr
¼
90
9
:
81
0
:
15
¼
132
:
44Nm
ð
9
Þ
M
s
—
the system torque, Nm. The angular velocity of the engine rotor:
n
mot
p
30
¼
2400
p
30
¼
2
1
s
x
mot
¼
251
:
ð
10
Þ
x
mot
—
angular velocity of cable drum motor, 1/s. The engine reach the maximum
speed during the time period
D
t
5 s. We assumed that the moment of the engine
inertia is equal to the reduced moment of the inertia of the load is described as:
¼
0
:
J
i
2
¼
0
:
01 kgm
2
J
¼
J
mot
þ
ð
11
Þ
the motor inertia moment, kgm
2
, The general moment of inertia of the motor
rotor is (
12
):
J
mot
—
J
i
2
¼
01 kgm
2
J
¼
J
mot
þ
0
:
ð
12
Þ
Resistance to the axis of the engine torque presented as (
12
):
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