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2
w
+
1
2
w
+
5
y
1
y
dy
+
w
y
dy
+
2
2
1
2
w
+
1
5
y
5
+
2
+
+
y
dy
=
6
w
+
12
w
2
2
2
w
5
and
2
w
+
1
2
w
+
5
y
1
dy
+
w
dy
+
2
2
1
2
w
+
1
5
y
5
+
2
+
+
dy
=
2
w
+
4
w
2
2
2
w
5
Fig. 13 Membership function for intermediate difficulty
In the third and the fourth rule we evaluate intermediate dif
culty D 2 (Fig. 13 ).
In the
fifth and the sixth rule we evaluate hard dif
culty D 3 (Fig. 14 ).
Z
ydy þ
Z
2w þ
3
6
2
3
2
2
3 w
27
2
3
2
wydy ¼
3w
þ
3
2w þ 3
and
Z
dy þ
Z
2w þ 3
6
2
3
2
2
wdy ¼ w
þ
3w
3
2w þ
3
2
w
+
3
6
y
3
2
27
3
2
y
dy
+
w
y
dy
=
w
3
w
+
2
2
3
2
3
2
w
+
3
and
2
w
+
3
6
y
3
2
dy
+
w
dy
=
w
+
3
w
2
2
3
2
w
+
3
Fig. 14 Membership function for hard difficulty
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