Digital Signal Processing Reference
In-Depth Information
Based on Eq. (11.5), and noting that 0
= 2 π/ K 0 , the DTFS coefficients are
given by
1
K 0
jn 0 k
D n
=
B sin( m 0 k + θ ) e
k =< K 0 >
e j( m 0 k ) e j( m 0 k )
2 j
1
K 0
j n 0 k
=
B
e
k =< K 0 >
k = K 0 e j( m n ) 0 k
k = K 0 e
B
2 K 0
B
2 K 0 e
e j θ
j θ
j( m + n ) 0 k
=− j
+
j
.
summation I
summation II
In proving Proposition 11.2, we used the following summation:
K 0 1
K 0
if k
= m
e j n 0 ( k m )
=
= m .
0i f k
n = 0
Therefore, summations I and II are given by
k = K 0 e j( m n ) 0 k
K 0
if n
= m
I =
=
0i f n
= m ;
k = K 0 e
K 0
if n
=− m
j( m + n ) 0 k
II =
=
0i f n
=− m ,
which results in the following values for the DTFS coefficients:
j B
2 e j θ
for n
= m
j B
D n
=
(11.18)
j θ
2 e
for n
=− m
0
elsewhere,
within one period ( m
m 1)).
As a special case, let us consider the DTFS for the following discrete sinu-
soidal sequence:
n
( K 0
2 π
7
k + π
4
y [ k ] = 3 sin
,
which has a fundamental period of K 0
= 7. Substituting B
= 3 , m
= 1, and
θ
= π /4 into Eq. (11.18), we obtain
j 3
2 e j 4
for n
= 1
j 3
j π
4
D n
=
(11.19)
2 e
for n
=− 1
0
elsewhere,
for 1 n 5. The magnitude and phase spectra for the sinusoidal sequence
are shown in Figs. 11.5(a) and (b).
Search WWH ::




Custom Search