Digital Signal Processing Reference
In-Depth Information
Fig. 9.6. Sampling and
reconstruction of a sinusoidal
signal g ( t ) = 5 cos(8000π t )at
a sampling rate of
6000 samples/s. CTFTs of:
(a) the sinusoidal signal g ( t );
(b) the impulse train s ( t ); (c) the
sampled signal g s ( t );
and (d) the signal reconstructed
with an ideal LPF H 1 (ω) with a
cut-off frequency of
6000π radians/s.
S ( w )
2 p (6000)
G ( w )
5 p
w
w
(1000 p )
(1000 p )
−24
−16
−8
0
8
16
24
−24
−16
−8
0
8 6 4
(a)
(b)
G s ( w )
Y ( w )
5 p
5 p (6000)
H 1 ( w )
w
w
−24
−16
−8
0
8
16
24
(1000 p )
−24
−16
−8
0
8
16
24
(1000 p )
(c)
(d)
The graphical representation of the sampling and reconstruction of the sinu-
soidal signal in the frequency domain is illustrated in Fig. 9.6. The CTFTs of
the sinusoidal signal g ( t ) and the impulse train s ( t ) are plotted, respectively,
in Fig. 9.6(a) and Fig. 9.6(b). Since the CTFT S ( ω )of s ( t ) consists of several
impulses, the CTFT G s ( ω ) of the sampled signal g s ( t ) is obtained by convolving
the CTFT G ( ω ) of the sinusoidal signal g ( t ) separately with each impulse in
G s ( ω ) and then applying the principle of superposition. To emphasize the results
of individual convolutions, a different pattern is used in Fig. 9.6(b) for each
impulse in S ( ω ). For example, the impulse δ ( ω ) located at origin in S ( ω )is
shown in Fig. 9.6(b) by a solid line. Convolving G ( ω ) with δ ( ω ) results in two
impulses located at ω = 8000 π , which are shown in Fig. 9.6(c) by solid lines.
Similarly for the other impulses in S ( ω ).
The output y ( t ) is obtained by applying G s ( ω ) to the input of an ideal LPF
with a cut-off frequency of 6000 π radians/s. Clearly, only the two impulses at
ω = 4000 π , corresponding to the sinusoidal signal cos(4000 π t ), lie within
the pass band of the lowpass filter. The remaining impulses are eliminated from
the output. This results in an output, y ( t ) =
cos(4000 π t ), which is different
from the original signal.
(ii)
The CTFT G s ( ω ) of the sampled signal with ω s
= 2 π (12 000) radians/s
( T s
= 1 / 12 000 s) is given by
G s ( ω ) = 12 000
G ( ω − 2 π m (12 000))
m =−∞
= 12 000
G ( ω − 24 000 m π ) .
m =−∞
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