Digital Signal Processing Reference
In-Depth Information
Fig. 9.6. Sampling and
reconstruction of a sinusoidal
signal
g
(
t
) = 5 cos(8000π
t
)at
a sampling rate of
6000 samples/s. CTFTs of:
(a) the sinusoidal signal
g
(
t
);
(b) the impulse train
s
(
t
); (c) the
sampled signal
g
s
(
t
);
and (d) the signal reconstructed
with an ideal LPF
H
1
(ω) with a
cut-off frequency of
6000π radians/s.
S
(
w
)
2
p
(6000)
G
(
w
)
5
p
…
…
w
w
(1000
p
)
(1000
p
)
−24
−16
−8
0
8
16
24
−24
−16
−8
0
8 6 4
(a)
(b)
G
s
(
w
)
Y
(
w
)
5
p
5
p
(6000)
H
1
(
w
)
…
…
w
w
−24
−16
−8
0
8
16
24
(1000
p
)
−24
−16
−8
0
8
16
24
(1000
p
)
(c)
(d)
The graphical representation of the sampling and reconstruction of the sinu-
soidal signal in the frequency domain is illustrated in Fig. 9.6. The CTFTs of
the sinusoidal signal
g
(
t
) and the impulse train
s
(
t
) are plotted, respectively,
in Fig. 9.6(a) and Fig. 9.6(b). Since the CTFT
S
(
ω
)of
s
(
t
) consists of several
impulses, the CTFT
G
s
(
ω
) of the sampled signal
g
s
(
t
) is obtained by convolving
the CTFT
G
(
ω
) of the sinusoidal signal
g
(
t
) separately with each impulse in
G
s
(
ω
) and then applying the principle of superposition. To emphasize the results
of individual convolutions, a different pattern is used in Fig. 9.6(b) for each
impulse in
S
(
ω
). For example, the impulse
δ
(
ω
) located at origin in
S
(
ω
)is
shown in Fig. 9.6(b) by a solid line. Convolving
G
(
ω
) with
δ
(
ω
) results in two
impulses located at
ω =
8000
π
, which are shown in Fig. 9.6(c) by solid lines.
Similarly for the other impulses in
S
(
ω
).
The output
y
(
t
) is obtained by applying
G
s
(
ω
) to the input of an ideal LPF
with a cut-off frequency of 6000
π
radians/s. Clearly, only the two impulses at
ω =
4000
π
, corresponding to the sinusoidal signal cos(4000
π
t
), lie within
the pass band of the lowpass filter. The remaining impulses are eliminated from
the output. This results in an output,
y
(
t
)
=
cos(4000
π
t
), which is different
from the original signal.
(ii)
The CTFT
G
s
(
ω
) of the sampled signal with
ω
s
=
2
π
(12 000) radians/s
(
T
s
=
1
/
12 000 s) is given by
∞
G
s
(
ω
)
=
12 000
G
(
ω −
2
π
m
(12 000))
m
=−∞
∞
=
12 000
G
(
ω −
24 000
m
π
)
.
m
=−∞
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