Digital Signal Processing Reference
In-Depth Information
h ( t )
x ( t )
2.0
1.5
t
t
−1
0
2
−2
0
3
(a)
(b)
h (− t )
h ( t t )
2.0
2.0
t
t
0
1
( t − 2)
( t +1)
0
−2
(c)
(d)
x ( t ), h ( t t )
case 1: t < −3
x ( t ), h ( t t )
case 2: −3 ≤ t < 0
2.0
2.0
1.5
1.5
t
t
( t − 2)
( t +1)
−2
0
3
3
( t − 2)
−2
0
( t +1)
(e)
(f)
x ( t ), h ( t t )
case 3: 0 ≤ t <1
case 4: 2 ≤ t < 5
x ( t ), h ( t t )
2.0
2.0
1.5
1.5
t
t
−2
0
( t − 2)
3
( t +1)
( t +1)
−2
( t − 2)
(g)
(h)
x ( t ), h ( t t )
case 5: t ≥ 5
2.0
Fig. 3.10. Convolution of the
input signal x ( t ) with the
impulse response h ( t )in
Example 3.9. Parts (a)-(i) are
discussed in the text.
1.5
t
−2
0
3
( t − 2)
( t +1)
(i)
Combining the five cases, we obtain
0
t < − 3
3( t + 3)
3 t
0
y ( t ) =
t
2
3(5 t )
2 t
5
0
t > 5 .
The waveform for the output response is sketched in Fig. 3.11.
Search WWH ::




Custom Search