Civil Engineering Reference
In-Depth Information
V
=-
1451 67
.
+
2000
= +
548 33
.
lb
34
-
548 33
8
.
v
=
= -
68 54
.
lf rightside
34
-
V
=
548 33
.
-
80 2
( )
=+
388 33
.
lb
45
-
388 33
8
.
v
=
= -
4
8854
.
lf left side
45
-
V
=
388 33
.
-
3500
=-
3111 67
.
lb
45
-
3111 67
8
.
v
=
= +
388 96
.
lf rightside
23
-
V
=-
3111 67
.
-
80 2
( )
= -
3271 7
.
lb
5
3271 7
8
.
v
=
= +
408
.96 plf
5
Determine wall net shears, basic wall shear
+
/
-
transfer diaphragm shear:
v
net
=+
458 3
.
-
(
179 8
.)
= +
278 53
.
plfleftsideo
ffsection 1
v
net
=+
458 3
.
-
(
159 8
.)
= +
298 53
.
plfright side
of section1
v
net
=+
458 3
.
-
(
409 8 853
.)
= +
.
plfleftsideof
section 2
v
net
=+
458 3
.
-
(
389 8 854
.)
= +
.
plfright side o
ffsection 2
v
net
=+
458 3 771
.
+
(
.
)
= +
506 04
.
plfleftsideo
ffsection 3
v
net
=+
458 3
.
+
(
181 5
.)
= +
639 83
.
plfright side
of section3
v
net
=+
458 3 854
.
-
(
.
)
= +
389 8
.
plfleftsideof
section 4
v
net
=+
458 3 854
.
-
(
.
)
= +
409 79
.
plfright side
of section4
v
net
=+
458 3
.
+
(
388 96
.
)
= +
846 66
.
plfleftside
of section5
v
net
=+
458 3
.
+
(
408 96
.
)
= +
867 3
.
plfright side
of section5
The directions of the shears transferred into the collectors and boundary members are
shown in the figure.
Determine the vertical collector forces (see Fig. 11.16):
F
left
=
278 58
.()
=
2228
lb
T
=- =
DL
2228
-
750
=
1478
lb reaction i
nleftboundarymember
left
joist
F
12
=
(
298 54
.
-
48 53 8
.
()
=
2000
lb
,
matchesoverturning force,
∴
OK
-
F
23
=
(
506 04
.
-
68 54 8
.
()
=
3500
lb
,
matchesoverturning force,
∴
OK
-
Search WWH ::
Custom Search