Civil Engineering Reference
In-Depth Information
V
D
65 6
20
.
v
=
B
TD
=
=+
328
.
plfpositiveunitshe
ar from shtg element
.
B
Transfer diaphragm TD4 (see Fig. 8.24):
262 530
40
.( )
V
A
=
=
196 88
.
lb
V
D
196 88
25
.
A
TD
v
=
=
=−
788
.
plfnegativeunits
hear from shtg element
.
A
262 510
40
.( )
V
B
=
=
65 6
.
lb
V
D
65 6
25
.
v
=
B
TD
=
=+
263
.
plfpositiveunitshe
ar from shtg element
.
B
Determination of diaphragm net shears (see Fig. 8.25):
Location (Grid Lines)
Net Shears
A from 1 to 2
−84 plf
B from 1 to 2
+84 plf
A from 2 to 3
v
= −84 − (9.84) = −93.84 plf
A +10′ (above) from 2 to 3
v
= −42 − (9.84) = −51.84 plf
A +10′ (below) from 2 to 3
v
= −42 + (3.28) = −38.72 plf
B (above) from 2 to 3
v
= +84 + (3.28) = +87.28 plf
B (below) from 2 to 4
−84 plf
D from 2 to 4
+84 plf
A from 3 to 5
−21 plf
A +10′ from 3 to 5
+21 plf
B (below) from 4 to 5
v
= −105 + (13.83) = −91.17 plf
D (above) from 4 to 5
v
= +63 + (13.83) = +76.8 plf
D (below) from 4 to 5
v
= +63 − (55.32) = +7.68 plf
E from 4 to 5
v
= +105 − (55.32) = +49.68 plf
A from 5 to 6
v
= −84 − (7.88) = −91.88 plf
A +10′ (above) from 5 to 6
v
= −42 − (7.88) = −49.88 plf
A +10′ (below) from 5 to 6
v
= −42 + (2.63) = −39.37 plf
B (above) from 5 to 6
v
= +84 + (2.63) = +86.63 plf
B (below) from 5 to 6
−105 plf
E from 5 to 6
+105 plf
A from 6 to 9
−303.61 plf
B (above) from 6 to 9
−135.63 plf
B (below) from 6 to 7
v
= +73.39 − (133.09) = −59.7 plf
B (below) from 7 to 8
v
= +73.39 + (104.09) = +177.48 plf
B (below) from 8 to 9
v
= +73.39 + (49.81) = +123.2 plf
C (above) from 6 to 7
v
=+220.39 − (133.09) =+87.3 plf
C (above) from 7 to 8
v
= +220.39 + (104.09) = +324.48 plf
C (above) from 8 to 9
v
= +220.39 + (49.81) = +270.2 plf
C (below) from 6 to 7
+521.92 plf
C (below) from 8 to 9
+95.16 plf
E from 6 to 7
+584.92 plf
E from 8 to 9
+158.16 plf
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