Civil Engineering Reference
In-Depth Information
Diaphragm 3:
wC
=
(
DL
)
D
=
0143025
.
()(
)
=
105
plf
s
wL
105 10
2
()
V
==
=
525
lb
support
2
It can safely be assumed that this shear is shared equally between TD1 and TD4.
525
2
F
=
=
262 . b
Diaphragm 1:
w
=
0143050
.
()(
)
=
210
plf
Diaphragm 2:
w
=
0143030
.
()(
)
=
126
plf
Transfer diaphragm TD1:
w
=
0143015 3
.
()(
)
=
lf
Main diaphragm:
Grid line A to B:
w
=
0143070
.
()(
)
=
294
plf from grid line o9
6
,
105
lf from
56
to
w
=
0143020 4
.
()(
)
=
lf from grid line o0
9
1
Grid line B to C:
w
=
0143070
.
()(
)
=
294
plf from grid line o9
6
,
105
lf from
56
to
Grid line C to E:
w
=
0143025
.
()(
)
=
105
plf from grid line o6
5
andfrom o
6
7
w
=
0143025
.
()(
)
=
105
plf from grid line o9
8
Construction of the basic shear diagrams (see Figs. 8.21 and 8.22):
Diaphragm 1:
RR
wL
AB
210 40
2
()
== =
=
4200
lb
2
R
D
4200
50
A
v
== =
84
plf,
v
= −
84
plf
A
B
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