Civil Engineering Reference
In-Depth Information
394 7
.
+
305 3
.
F
2
=
()
16
=+
5600
lb tension
B
2
The strut force at grid line 3B is equal to
(
465 9926
.
-
.) (
+
423 1498
.
-
.)
()
F
3
B
=+
5600
-
15
=
0
lb tension
2
The strut force at grid line 2C is equal to
394 7
.
+
317 8
.
F
2
=
()
16
=+
5700
lb compression
C
2
The strut force at grid line 3C equals
(
465 9865
.
-
.) (
+
423 1437
.
-
.)
()
F
3
=
5700
-
15
=
0
l
bbcompression
C
2
All the longitudinal force diagrams close to zero and follow basic diaphragm action.
Determination of transverse collector/chord forces (see Fig. 4.15):
Starting at grid line 1A, the
strut force at the end of the wall is equal to
v
net
=+141
plfnet shearatshear walls prev
iously calculated
FvL
=
= +
141 12
()
= +
1692
lb tension
netSW
1
F
i g u r e
4.15 Transverse strut/collector force diagrams.
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