Diaphragms With End Horizontal Offsets - The Analysis of Irregular Shaped Structures - page 144

V
D

4000
50

2

v = = = 80 plf

2 R

right

VVw
3

=- () 15 = 4000 - 200 15 () = 1000 lb

2

1000
50

v 3 = = 20 plf

VRw
5

=- () 90 = 12000 - 200 90 () =- 6000 lb

1

= -

6000
20

v =- 300 plfright side of grid li , ne 5

5 R

= -

6000
50

v =- 120 plf eftsideofgrid lin , ee5

5 L

VRw
4

=- () 75 = 12 000 , - 200 75 ( ) =- 3000 lbshear attgrid line4

1

= -

3000
50

=- plf 60

v 4

Calculation of the chord forces at the discontinuities (see Fig. 3.36):

wx

2

200 40
2

()

2

MRx =- = 12 000 40 , ( ) - = 320 000 , ft-lbatgrid line2

2 1

2

M
D

320 000
36

,

2

F == = 8889 lb tensionatgrid line 2 C

2

2 2

wx 200 30

2

()

MRx =- = 12 000 30 , ( ) - = 270 000 , ft-lbatgrid line5

5 6

2

M
D

270 000
20

,

6

F == = 13 500 , lbcompression at grid line5

2

Determination of the transfer diaphragm shears (see Fig. 3.36):
Transfer diaphragm TD1:

8889 36
50

() 6400

15

V = = 6400 lb v = = 426 7 . plf

D D

8889 14
50

() 2489

15

V = = 2489 lb v = = - 165 9 . plf

A A

Transfer diaphragm TD2:

13 500 30
50

, ( ) 8100

15

V = = 8100 lb v = = 540 plf

D D

13 500 20
50

, ( ) 5400

15

V = = 5400 lb v = = - 360 plf

A A