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know the exact mass of the earth, how can we make M rigorously equal to
M ?
Subsequently, we will see that the first-degree harmonic can always be
assumed to be zero. Under this assumption, we can substitute (2-331) into
(2-328) and express T by the conventional Stokes formula (2-304). Thus we
obtain
gS ( ψ ) dσ .
T = GδM
R
R
4 π
+
(2-333)
σ
This is the generalization of Stokes' formula for T . It holds for an arbitrary
reference ellipsoid whose center coincides with the center of the earth.
First-degree terms
The coecients of the first-degree harmonic in the potential W are, according
to (2-85) and (2-87), given by
GM x c ,GMy c ,GM c ,
(2-334)
where x c ,y c ,z c are the rectangular coordinates of the earth's center of grav-
ity. For the normal potential U , we have the analogous quantities
GM x c ,GM y c ,GM z c .
(2-335)
As x c ,y c ,z c are very small in any case, these are practically equal to
GM x c ,GMy c ,GMz c .
(2-336)
The coecients of the first-degree harmonic in the anomalous potential T =
W
U are, therefore, equal to
x c ) ,GM ( y c
y c ) ,GM ( z c
z c ) .
GM ( x c
(2-337)
They are zero, and there is no first-degree harmonic T 1 ( ϑ, λ ) if and only if
the center of the reference ellipsoid coincides with the center of gravity of
the earth . This is usually assumed.
In the general case, we find from the first-degree term of (2-76), on
putting r = R and using the coecients (2-85) together with (2-87),
R 2 ( z c
T 1 ( ϑ, λ )= GM
z c ) P 10 (cos ϑ )+( x c
x c ) P 11 (cos ϑ )cos λ
(2-338)
y c ) P 11 (cos ϑ )sin λ .
+( y c
If the origin of the coordinate system is taken to be the center of the reference
ellipsoid, then x c = y c = z c =0.With P 10 (cos ϑ )=cos ϑ, P 11 (cos ϑ )=sin ϑ ,
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