Civil Engineering Reference
In-Depth Information
then its elastic buckling load
N
cr
can be expressed in the general form of
equation 3.23 when the effective length ratio
k
cr
=
L
cr
/
L
is the solution of
γ
1
γ
2
(π/
k
cr
)
2
−
36
6
(γ
1
+
γ
2
)
=
π
k
cr
cot
π
k
cr
,
(3.46)
where the relative stiffness of the unbraced member at its end 1 is
γ
1
=
(
6
EI
/
L
)
12
(3.47)
α
1
in which the summation
1
α
is for all the other members at end 1, and
γ
2
is
similarly defined.The relative stiffnesses may also be expressed as
(
6
EI
/
L
)
12
1.5
1
γ
1
1.5
+
γ
1
k
1
=
α
+
(
6
EI
/
L
)
12
=
(3.48)
and a similar definition of
k
2
. Values of the effective length ratio
L
cr
/
L
which
satisfy equation 3.46 are presented in chart form in Figure 3.21b.
In using the chart of Figure 3.21b, the stiffness factors
k
may be calculated
fromequation3.48byusingthestiffnessapproximationsofFigure3.19.Thusfor
braced restraining members of the third type shown in Figure 3.19a,
(
I
/
L
)
12
1.5
1
k
1
=
(
I
/
L
)(
1
−
N
/
4
N
cr
,
L
)
+
(
I
/
L
)
12
.
(3.49)
3.6.6 Bracing stiffness required for a braced member
The elastic buckling load of an unbraced compression member may be increased
substantially by providing a translational bracing system which effectively pre-
vents sway. The bracing system need not be completely rigid, but may be elastic
as shown in Figure 3.22, provided its stiffness
α
exceeds a certain minimum
value
α
L
. It is shown in Section 3.10.6 that the minimum value for a pin-ended
compression member is
α
L
=
π
2
EI
/
L
3
.
(3.50)
This conclusion can be extended to compression members with rotational end
restraints, and it can be shown that if the sway bracing stiffness
α
is greater than
α
L
=
N
cr
/
L
,
(3.51)
where
N
cr
is the elastic buckling load for the braced mode, then the member is
effectively braced against sway.
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