Civil Engineering Reference
In-Depth Information
then its elastic buckling load N cr can be expressed in the general form of
equation 3.23 when the effective length ratio k cr = L cr / L is the solution of
γ 1 γ 2 (π/ k cr ) 2 36
6 1 + γ 2 )
= π
k cr cot π
k cr ,
(3.46)
where the relative stiffness of the unbraced member at its end 1 is
γ 1 = ( 6 EI / L ) 12
(3.47)
α
1
in which the summation
1 α is for all the other members at end 1, and γ 2 is
similarly defined.The relative stiffnesses may also be expressed as
( 6 EI / L ) 12
1.5
1
γ 1
1.5 + γ 1
k 1 =
α + ( 6 EI / L ) 12 =
(3.48)
and a similar definition of k 2 . Values of the effective length ratio L cr / L which
satisfy equation 3.46 are presented in chart form in Figure 3.21b.
In using the chart of Figure 3.21b, the stiffness factors k may be calculated
fromequation3.48byusingthestiffnessapproximationsofFigure3.19.Thusfor
braced restraining members of the third type shown in Figure 3.19a,
( I / L ) 12
1.5
1
k 1 =
( I / L )( 1 N / 4 N cr , L ) + ( I / L ) 12 .
(3.49)
3.6.6 Bracing stiffness required for a braced member
The elastic buckling load of an unbraced compression member may be increased
substantially by providing a translational bracing system which effectively pre-
vents sway. The bracing system need not be completely rigid, but may be elastic
as shown in Figure 3.22, provided its stiffness α exceeds a certain minimum
value α L . It is shown in Section 3.10.6 that the minimum value for a pin-ended
compression member is
α L = π 2 EI / L 3 .
(3.50)
This conclusion can be extended to compression members with rotational end
restraints, and it can be shown that if the sway bracing stiffness α is greater than
α L = N cr / L ,
(3.51)
where N cr is the elastic buckling load for the braced mode, then the member is
effectively braced against sway.
 
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