Civil Engineering Reference
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torque T w = T x acting on the I-section is replaced by two transverse shears
V f = T x / d f ,
(10.50)
one on each flange. The bending deflections v f of each flange can then be deter-
minedbyelasticanalysisorbyusingavailablesolutions[4],andthetwistrotations
can be calculated from
φ w = 2 v f / d f
(10.51)
10.3.2.3 Non-uniform torsion
When neither the torsional rigidity nor the warping rigidity can be neglected, as
in hot-rolled steel I- and channel sections, the applied torque is resisted by a
combination of the uniform and warping torques, so that
T x = T t + T w .
(10.52)
In this case, the differential equation of non-uniform torsion is
d x EI w d 3 φ
T x = GI t d φ
d x 3 ,
(10.53)
the general solution of which can be written as
φ = p ( x ) + A 1 e x / a + A 2 e x / a + A 3 ,
(10.54)
where
a 2 = EI w
GI t = K 2 L 2
π 2 .
(10.55)
The function p ( x ) in this solution is a particular integral whose form depends
on the variation of the torque T x along the beam. This can be determined by the
standard techniques used to solve ordinary linear differential equations (see [16]
forexample).Thevaluesoftheconstantsofintegration A 1 , A 2 , and A 3 dependon
the form of the particular integral and on the boundary conditions.
Completesolutionsforanumberoftorquedistributionsandboundaryconditions
have been determined, and graphical solutions for the twist φ and its derivatives
d φ /d x ,d 2 φ /d x 2 ,andd 3 φ /d x 3 areavailable[5,6].Asanexample,thenon-uniform
torsion of the cantilever shown in Figure 10.28 is analysed in Section 10.8.5.
Sometimes the accuracy of the method of solution described above is not
required, in which case a much simpler method may be used. The maximum
angle of twist rotation φ m may be approximated by
φ tm φ wm
φ tm + φ wm
φ m =
(10.56)
in which φ tm is the maximum uniform torsion angle of twist rotation obtained by
solving equation 10.8 with T t = T x , and φ wm is the maximum warping torsion
 
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