Civil Engineering Reference
In-Depth Information
Section resistance.
t f = 12.5 mm, f y = 275 N / mm 2
EN10025-2
ε =
( 235 / 275 ) = 0.924
T5.2
c f /( t f ε) = ( 204.3 / 2 7.9 / 2 10.2 )/( 12.5 × 0.924 ) = 7.62 < 9
T5.2
and the flange is Class 1. T5.2
The worst case for the web classification is when the web is fully plastic in
compression, for which
c w /( t w ε) = ( 206.2 2 × 12.5 2 × 10.2 )/( 7.9 × 0.924 ) = 22.0 < 33
T5.2
and the web is Class 1.
T5.2
Thus the section is Class 1.
γ M 0 = 1.0 6.1
N c , Rd = 66.3 × 10 2 × 275 / 1.0 N = 1823 kN = N pl , Rd 6.2.4(2)
0.25 N pl , Rd = 0.25 × 1826 = 455.8 kN > 137.2 kN = N Ed , 6.2.9.1(4)
0.5 h w t w f y = 0.5 ( 206.2 2 × 12.5 ) × 7.9 × 275 N = 196.8 kN 6.2.9.1(4)
> 137.2 kN = N Ed ,
and so no allowance need be made for the effect of axial force on the plastic
resistance moment.
6.2.9.1(4)
M N , Rd = M pl , Rd = 567 × 10 3 × 275 / 1.0 Nmm
= 155.9 kNm > 144.8 kNm = M Ed
6.2.9.1(5)
and the section resistance is adequate.
6.2.9.1(2)
Member resistance.
Becausethememberiscontinuouslybracedout-of-plane,beamlateralbuckling
and column minor axis and torsional buckling need not be considered.
Thus M z , Ed = 0, χ LT = 1.0, and
λ 0 = 0, C mLT = 1.0, a LT = 0, and b LT = 0
TA.1
L cr = 5000
5.2.2.(7b)
 
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