Civil Engineering Reference
In-Depth Information
µ z
1 N Ed / N cr , y
1
C zy 0.6
w y
w z = 0.990
k zy = C my C mLT
0.746
1 200 / 1417 ×
1
0.716 × 0.6 ×
1.115
1.5
× 1.287 ×
= 0.800 TA.1
µ z
1 N Ed / N cr , z
1
C zz = 0.804 ×
0.746
1 200 / 584.4 ×
1
0.888 = 1.027
TA.1
k zz = C mz
N b , y , Rd + k yy M y , Ed
N Ed
M b , Rd + k yz M z , Ed
M z , Rd = 200
900 + 1.508 × 45.0
121.4
+ 1.115 × 8.1
32.7 = 0.222 + 0.559 + 0.276 = 1.057 > 1
N b , z , Rd + k zy M y , Ed
N Ed
M b , Rd + k zz M z , Ed
M z , Rd = 200
449 + 0.800 × 45.0
121.4 + 1.027
× 8.1
32.7 = 0.445 + 0.296 + 0.254 = 0.995 < 1
and the member resistance appears to be inadequate.
7.8 Unworked examples
7.8.1 Example 6 - non-linear analysis
Analyse the non-linear elastic in-plane bending of the simply supported beam-
column shown in Figure 7.20a, and show that the maximum moment M max may
be closely approximated by using the greater of M max = qL 2 / 8 and
M max = 9 qL 2
128
( 1 0.29 N / N cr , y )
( 1 N / N cr , y )
in which N cr , y = π 2 EI y / L 2 .
7.8.2 Example 7 - non-linear analysis
Analyse the non-linear elastic in-plane bending of the propped cantilever shown
in Figure 7.20b, and show that the maximum moment M max may be closely
approximated by using
qL 2 / 8 ( 1 0.18 N / N cr , y )
M max
( 1 0.49 N / N cr , y )
in which N cr , y = π 2 EI y / L 2 .
 
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