Civil Engineering Reference
In-Depth Information
µ
z
1
−
N
Ed
/
N
cr
,
y
1
C
zy
0.6
w
y
w
z
=
0.990
k
zy
=
C
my
C
mLT
0.746
1
−
200
/
1417
×
1
0.716
×
0.6
×
1.115
1.5
×
1.287
×
=
0.800 TA.1
µ
z
1
−
N
Ed
/
N
cr
,
z
1
C
zz
=
0.804
×
0.746
1
−
200
/
584.4
×
1
0.888
=
1.027
TA.1
k
zz
=
C
mz
N
b
,
y
,
Rd
+
k
yy
M
y
,
Ed
N
Ed
M
b
,
Rd
+
k
yz
M
z
,
Ed
M
z
,
Rd
=
200
900
+
1.508
×
45.0
121.4
+
1.115
×
8.1
32.7
=
0.222
+
0.559
+
0.276
=
1.057
>
1
N
b
,
z
,
Rd
+
k
zy
M
y
,
Ed
N
Ed
M
b
,
Rd
+
k
zz
M
z
,
Ed
M
z
,
Rd
=
200
449
+
0.800
×
45.0
121.4
+
1.027
×
8.1
32.7
=
0.445
+
0.296
+
0.254
=
0.995
<
1
and the member resistance appears to be inadequate.
7.8 Unworked examples
7.8.1 Example 6 - non-linear analysis
Analyse the non-linear elastic in-plane bending of the simply supported beam-
column shown in Figure 7.20a, and show that the maximum moment
M
max
may
be closely approximated by using the greater of
M
max
=
qL
2
/
8 and
M
max
=
9
qL
2
128
(
1
−
0.29
N
/
N
cr
,
y
)
(
1
−
N
/
N
cr
,
y
)
in which
N
cr
,
y
=
π
2
EI
y
/
L
2
.
7.8.2 Example 7 - non-linear analysis
Analyse the non-linear elastic in-plane bending of the propped cantilever shown
in Figure 7.20b, and show that the maximum moment
M
max
may be closely
approximated by using
qL
2
/
8
≈
(
1
−
0.18
N
/
N
cr
,
y
)
M
max
(
1
−
0.49
N
/
N
cr
,
y
)
in which
N
cr
,
y
=
π
2
EI
y
/
L
2
.
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