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N b , z , Rd + k zy M y , Ed
N Ed
M b , Rd = 200
449 + 0.793 × 45.0
121.4 = 0.445 + 0.294 = 0.739 < 1
6.3.3(4)
and the member out-of-plane resistance is adequate.
7.7.5Example - checking the biaxial bending capacity
Problem. The 9m long simply supported beam-column shown in Figure 7.19c
and d has a factored design axial compression force of 200kN, a factored design
concentrated load of 20kN (which includes an allowance for self-weight) acting
in the major principal plane, and a factored design uniformly distributed load
of 3.2kN/m acting in the minor principal plane. Lateral deflections v and twist
rotations φ are prevented at the ends and at mid-span. The beam-column is the
254 × 146UB37ofS275steelshowninFigure7.19a.Checktheadequacyofthe
beam-column.
Design bending moments.
M y , Ed = 45.0kNm ( Section 7.7.2 ) , M z , Ed = 8.1 kNm ( Section 7.7.3 )
Simplified approach for cross-section resistance.
Combining the calculations of Sections 7.7.2 and 7.7.3,
200 × 10 3
47.2 × 10 2 × 275 / 1.0 + 45.0
132.8 + 8.1
32.7 = 0.740 < 1
6.2.1(7)
and the cross-section resistance is adequate.
Alternative approach for cross-section resistance.
AsshowninSections7.7.2and7.7.3,theaxialloadissufficientlylowforthereisto
benoreductioninthemomentresistanceabouteitherthemajorortheminoraxis.
n = N Ed / N pl , Rd = 200 × 10 3 /( 47.2 × 10 2 × 275 / 1.0 ) = 0.154,
β = 5 n = 0.770
6.2.9.1(6)
M y , Ed
M N , y , Rd
α
M z , Ed
M N , z , Rd
β
45.0
132.8
2
8.1
32.7
0.770
+
=
+
= 0.456 1
6.2.9.1(6)
and the cross-section resistance is adequate.
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