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N
b
,
z
,
Rd
+
k
zy
M
y
,
Ed
N
Ed
M
b
,
Rd
=
200
449
+
0.793
×
45.0
121.4
=
0.445
+
0.294
=
0.739
<
1
6.3.3(4)
and the member out-of-plane resistance is adequate.
7.7.5Example - checking the biaxial bending capacity
Problem.
The 9m long simply supported beam-column shown in Figure 7.19c
and d has a factored design axial compression force of 200kN, a factored design
concentrated load of 20kN (which includes an allowance for self-weight) acting
in the major principal plane, and a factored design uniformly distributed load
of 3.2kN/m acting in the minor principal plane. Lateral deflections
v
and twist
rotations
φ
are prevented at the ends and at mid-span. The beam-column is the
254
×
146UB37ofS275steelshowninFigure7.19a.Checktheadequacyofthe
beam-column.
Design bending moments.
M
y
,
Ed
=
45.0kNm
(
Section 7.7.2
)
,
M
z
,
Ed
=
8.1 kNm
(
Section 7.7.3
)
Simplified approach for cross-section resistance.
Combining the calculations of Sections 7.7.2 and 7.7.3,
200
×
10
3
47.2
×
10
2
×
275
/
1.0
+
45.0
132.8
+
8.1
32.7
=
0.740
<
1
6.2.1(7)
and the cross-section resistance is adequate.
Alternative approach for cross-section resistance.
AsshowninSections7.7.2and7.7.3,theaxialloadissufficientlylowforthereisto
benoreductioninthemomentresistanceabouteitherthemajorortheminoraxis.
n
=
N
Ed
/
N
pl
,
Rd
=
200
×
10
3
/(
47.2
×
10
2
×
275
/
1.0
)
=
0.154,
β
=
5
n
=
0.770
6.2.9.1(6)
M
y
,
Ed
M
N
,
y
,
Rd
α
M
z
,
Ed
M
N
,
z
,
Rd
β
45.0
132.8
2
8.1
32.7
0.770
+
=
+
=
0.456
≤
1
6.2.9.1(6)
and the cross-section resistance is adequate.
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