Civil Engineering Reference
In-Depth Information
FromSection7.7.3,
N
b
,
z
,
Rd
=
449kN,
χ
z
=
0.346,
λ
z
=
1.490,
λ
max
=
1.490,
N
cr
,
z
=
584.4 kN, and
w
z
=
1.5.
ψ
=
0,
C
mLT
=
0.6
+
0.4
ψ
=
0.6
>
0.4
TB.3
0.1
λ
z
(
C
mLT
−
0.25
)
N
Ed
χ
z
N
Rk
/γ
M
1
1
−
1
−
0.1
×
1.490
200
×
10
3
0.346
×
47.2
×
10
2
×
275
/
1.0
=
(
0.6
−
0.25
)
×
=
0.810
0.1
(
C
mLT
−
0.25
)
N
Ed
χ
z
N
Rk
/γ
M
1
1
−
1
−
200
×
10
3
0.346
×
47.2
×
10
2
×
275
/
1.0
0.1
(
0.6
−
0.25
)
×
=
=
0.873 TB.1
k
zy
=
0.873
TB.1
N
b
,
z
,
Rd
+
k
zy
M
y
,
Ed
N
Ed
M
b
,
Rd
=
200
449
+
0.873
×
45.0
121.4
=
0.445
+
0.324
=
0.769
<
1
6.3.3(4)
and the member out-of-plane resistance is adequate.
Beam-column member buckling resistance - more exact approach (Annex A).
The member in-plane resistance was checked in Section 7.7.2, but as for the sim-
plified approach, equation 6.61 should be checked by taking the lateral buckling
resistance in place of the in-plane major axis bending resistance. The interaction
factor
k
yy
also requires re-calculating due to the possibility of lateral buckling.
λ
y
=
0.960,
λ
max
=
λ
z
=
1.490
TA.1
Using
M
zx
=
111.2 kNm from Section 6.15.2,
λ
0
=
132.8
/
111.2
=
1.093
TA.1
Since cross-section is doubly-symmetrical, using equation 7.37 with
(
5537
×
10
4
+
571
×
10
4
)/
47.2
×
10
2
i
p
=
(
I
y
+
I
z
)/
A
=
=
113.8 mm,
GI
t
+
π
2
EI
w
N
cr
,
T
=
1
i
p
L
cr
,
T
81000
×
15.3
×
10
4
+
π
2
×
210000
×
0.0857
×
10
12
4500
2
1
113.8
2
=
=
1636 kN.
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