Civil Engineering Reference
In-Depth Information
Alternative approach for cross-section resistance.
Because the section is Class 2, Clause 6.2.9.1 can be used.
N
Ed
=
200 kN
<
406 kN
=
(
256
−
2
×
10.9
)
×
6.3
×
275
=
h
w
t
w
f
y
γ
M
0
.
6.2.9.1(4)
1.0
×
10
3
and so no reduction in plastic moment resistance is required.
Thus
M
N
,
z
,
Rd
=
M
pl
,
z
,
Rd
=
32.7 kNm
>
8.1 kNm
=
M
z
,
Ed
6.2.5(2)
and the cross-section resistance is adequate.
Compression member buckling resistance.
N
cr
,
z
=
L
cr
,
z
Af
y
1
λ
1
=
4500
(
3.48
×
10
)
1
93.9
×
0.924
=
1.490 6.3.1.3(1)
λ
z
=
i
z
For a rolled UB section (with
h
/
b
>
1.2 and
t
f
≤
40 mm), buckling about the
z
-axis, use buckling curve (b) with
α
=
0.34
T6.2,T6.1
Φ
z
=
0.5
[
1
+
0.34
(
1.490
−
0.2
)
+
1.490
2
]=
1.829
6.3.1.2(1)
χ
z
=
1
/(
1.829
+
1.829
2
−
1.490
2
)
=
0.346
6.3.1.2(1)
N
b
,
z
,
Rd
=
χ
z
Af
y
/γ
M
1
=
0.346
×
47.2
×
10
2
×
275
/
1.0 N
=
449 kN
>
200 kN
=
N
Ed
6.3.1.1(3)
Beam-column member resistance - simplified approach (Annex B).
Because the member is bent about the minor axis, beam lateral buckling need not
be considered, and
e
LT
=
0.
M
h
=−
8.1 kNm,
M
s
=
9
×
3.2
×
4.5
2
/
128
=
4.56 kNm,
ψ
=
0 TB.3
α
s
=
M
s
/
M
h
=
4.56
/(
−
8.1
)
=−
0.563,
TB.3
C
mz
=
0.1
−
0.8
α
s
=
0.1
−
0.8
×
(
−
0.563
)
=
0.550
>
0.40
TB.3
1
+
(
2
×
1.490
−
0.6
)
N
Ed
χ
z
N
Rk
/γ
M
1
C
mz
1
+
(
2
λ
z
−
0.6
)
=
0.550
×
200
×
10
3
0.346
×
47.2
×
10
2
×
275
/
1.0
×
=
1.133
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