Civil Engineering Reference
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and the maximum moment obtained by substituting equation 7.74 into equation
7.73 is
+
2
-
.
0.5
N
N
cr
,
y
+
cot
π
N
N
cr
,
y
,
1
+
M
max
=
M
β
m
cosec
π
.
(7.3)
When
β
m
>
−
cos
π
√
(
N
/
N
cr
,
y
)
,
x
max
is negative, in which case the maximum
moment in the beam-column is the end moment
M
at
x
=
0, whence
M
max
=
M
,
(7.4)
For beam-columns which are bent in single curvature by equal and opposite
endmoments
(β
m
=−
1
)
, equation7.1forthedeflectedshapesimplifies, andthe
central deflection
δ
max
can be expressed non-dimensionally as
8
/π
2
N
/
N
cr
,
y
δ
max
δ
sec
π
2
N
N
cr
,
y
−
1
=
(7.5)
inwhich
δ
=
ML
2
/
8
EI
y
isthevalueof
δ
max
when
N
=
0.Themaximummoment
occurs at the centre of the beam-column, and is given by
M
max
=
M
sec
π
2
N
N
cr
,
y
.
(7.6)
Equations 7.5 and 7.6 are plotted in Figure 7.4.
7.5.2 Beam-columns with initial curvature
If the beam-column shown in Figure 7.3 is not straight, but has an initial
crookedness given by
w
0
=
δ
0
sin
π
x
/
L
,
then the differential equation of bending becomes
−
EI
y
d
2
w
d
x
2
=
M
−
M
(
1
+
β
m
)
x
L
+
N
(
w
+
w
0
)
.
(7.75)
The solution of this equation which satisfies the support conditions of
(
w
)
0
=
(
w
)
L
=
0is
w
=
(
M
/
N
)
[
cos
µ
x
−
(β
m
cosec
µ
L
+
cot
µ
L
)
sin
µ
x
−
1
+
(
1
+
β
m
)
x
/
L
]+[
(µ
L
/π)
2
/
{
1
−
(µ
L
/π)
2
}]
δ
0
sin
π
x
/
L
,
(7.76)
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