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Proof.
Let us fix
r, n, p, i, A,
and
B
as in the lemma. By Lemma
4
, if a coordinate
is irrelevant for
A
, then it is also irrelevant for
B
and vice versa.
In the case
n
=
r
,wehave
A
=
B
and this family must be a singleton, so
that the lemma is trivially true. From now on, we assume that
n>r
and hence
the notion of
r
-cross-intersecting families is meaningful for
n
−
1 coordinates.
Let
q
=(
p
1
,...,p
i−
1
,p
i
+1
,...,p
n
). For any
l
∈
[
p
i
], let
A
l
=
{
x
∈
A
:
x
i
=
l
}
,
B
l
=
,
and let
A
l
and
B
l
stand for the families obtained from
A
l
and
B
l
, respectively,
by dropping their
i
th coordinates. By definition, we have
A
l
,B
l
ↆ
{
y
∈
B
:
y
i
=
l
}
S
q
,and
|
A
|
=
l
|
=
l
|
[
p
i
]
,
the families
A
l
and
B
m
are
r
-cross-intersecting, since the vectors in
A
l
differ from
the vectors in
B
m
in the
i
th coordinate, and therefore the
r
indices where they
agree must be elsewhere.
Let
Z
denote the maximum product
A
l
|
and
|
B
|
B
l
|
. Furthermore, for any two distinct elements
l, m
∈
A
∗
|·|
B
∗
|
|
of an
r
-cross-intersecting
pair
A
∗
,B
∗
=
m
.
Adding an irrelevant
i
th coordinate to the maximal
r
-cross-intersecting pair
A
∗
,B
∗
ↆ
ↆ
S
q
.Wehave
|
A
l
|·|
B
m
|≤
Z
for all
l, m
∈
[
p
i
] with
l
S
q
, we obtain a pair
A
∗
,B
∗
ↆ
S
p
with
|
A
∗
|·|
B
∗
|
=
p
i
Z
. Thus, using
the maximality of
A
and
B
,wehave
|
A
|·|
B
|≥
p
i
Z
.Let
l
0
be chosen so as to
maximize
|
A
l
0
|·|
B
l
0
|
, and let
c
=
|
A
l
0
|·|
B
l
0
|
/Z
.
Assume first that
c
≤
1. Then we have
p
i
Z
Z
=
p
i
Z.
≤|
A
|·|
B
|
=
[
p
i
]
|
A
l
|·|
B
m
|≤
l,m
∈
l,m
∈
[
p
i
]
Hence, we must have equality everywhere. This yields that
c
= 1 and that
A
l
and
B
m
form a maximal
r
-cross-intersecting pair for all
l, m
∈
[
p
i
],
l
=
m
. This
also implies that
|
A
l
|
=
|
A
m
|
for
l, m
∈
[
p
i
], from where the statement of the
lemma follows, provided that
p
i
=2.
If
p
i
≥
3, then all families
A
l
must be equal to one another, since one member
in a maximal
r
-cross-intersecting family determines the other (by Lemma
4
). This
contradicts our assumption that the
i
th coordinate was relevant for
A
.
Thus, we may assume that
c>
1.
For
m
∈
[
p
i
],
m
=
l
0
,wehave
|
A
l
0
|·|
B
m
|≤
Z
=
|
A
l
0
|·|
B
l
0
|
/c
.Thus,
|
B
m
|≤|
B
l
0
|
/c,
(1)
=
m∈
[
p
i
]
|
which yields that
|
B
|
B
m
|≤
(1 + (
p
i
−
1)
/c
)
|
B
l
0
|
. By symmetry, we
also have
|
A
m
|≤|
A
l
0
|
/c
(2)
for
m
=
l
0
and
|
A
|≤
(1 + (
p
i
−
1)
/c
)
|
A
l
0
|
. Combining these inequalities, we
obtain
p
i
Z
1)
/c
)
2
1)
/c
)
2
cZ.
≤|
A
|·|
B
|≤
(1 + (
p
n
−
|
A
l
0
|·|
B
l
0
|
=(1+(
p
i
−
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