Environmental Engineering Reference
In-Depth Information
Flow through a Pipeline
Q
(cfs) = 0.785 × (
D
)
2
(ft) × Velocity (ft/sec)
(2.5)
■
Example 2.64
Problem:
What is the flow in cfs for a 2-ft-diameter pipe flowing full at a velocity
of 2.8 ft/sec?
Solution
:
Q
= 0.785 × (
D
)
2
(ft) × Velocity (ft/sec) = 0.785 × (2 ft)
2
× 2.8 ft/sec = 8.79 cfs
When converting flow rates, the most common flow conversions are 1 cfs = 449
gpm and 1 gpm = 1440 gpd. Also, MGD × 700 = gpm. To convert gallons per day to
MGD, divide the gpd by 1,000,000. For example, convert 150,000 gallons to MGD:
150,000 gpd ÷ 1,000,000 = 0.150 MGD
In some instances, flow is given in MGD but is needed in gpm. To make the con-
version from MGD to gpm, two steps are required.
1. Convert the gpd by multiplying by 1,000,000.
2. Convert to gpm by dividing by the number of minutes in a day (1440 min/
day).
■
Example 2.65
Problem:
Convert 0.135 MGD to gpm.
Solution:
1. Convert the flow in MGD to gpd:
0.135 MGD × 1,000,000 = 135,000 gpd
2. Convert to gpm by dividing by the number of minutes in a day (24 hr/day ×
60 min/hr = 1440 min/day):
135,000 gpd ÷ 1440 min/day = 94 gpm
To determine flow through a pipeline, channel, or stream, we use the following
equation:
Q
=
V
×
A
(2.6)
where
Q
= Cubic feet per second (cfs).
V
= Velocity in feet per second (ft/sec).
A
= Area in square feet (ft
2
).
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