Basic Units of Measurement and Conversions - Basic Mathematics for Water and Wastewater Operators - page 29

■ Example 2.54
Problem : Find the density (lb/ft 3 ) of a certain oil that has a specific gravity of 0.94.
Solution:
Density = Specific gravity × 62.4 lb/ft 3 = 0.94 × 62.4 lb/ft 3 = 58.7 lb/ft 3
■ Example 2.55
Problem : Find the density (lb/gal) of a liquid chemical that has a specific gravity of
1.555.
Solution :
Density = Specific gravity × 8.34 lb/gal = 1.555 × 8.34 lb/gal = 12.9 lb/gal
■ Example 2.56
Problem : Find the density (lb/gal) of caustic soda, which has a specific gravity of 1.530.
Solution :
Density = Specific gravity × 8.34 lb/gal = 1.530 × 8.34 lb/gal = 12.8 lb/gal
■ Example 2.57
Problem : Find the density (lb/ft 3 ) of potassium permanganate, which has a specific
gravity of 2.703.
Solution :
Density = Specific gravity × 62.4 lb/ft 3 = 2.703 × 62.4 lb/ft 3 = 168.7 lb/ft 3
■ Example 2.58
Problem : A tank holds 1440 gal of a liquid chemical. The specific gravity is 0.95.
How many pounds of liquid are in the tank?
Solution :
Density = Specific gravity × 8.34 lb/gal = 0.95 × 8.34 lb/gal = 7.92 lb/gal
7.92 lb/gal × 1440 gal = 11,404.8 lb
■ Example 2.59
Problem: The pump rate desired is 30 gpm, and the weight of the liquid is 82.2 lb/ft 3 .
How many pounds of liquid can be pumped per day?