Environmental Engineering Reference
In-Depth Information
Example 2.13
Convert pounds to milligrams per liter.
Quantity (lb)
Volume (M
Concentration(mg/L)
=
G)
×
8.34 lb/MG/mg/L
Problem: An aeration tank contains 89,990 lb of solids. The volume of the aeration
tank is 4.45 MG. What is the concentration of solids in the aeration tank in milli-
grams per liter?
Solution:
Quantity (lb)
Volume (MG)
Concentration
=
×
8.34
lb/MG/mg/L
89,990 lb
=
=
2425 mg/L
4.45 MG
×
8.34 lb/MG/mg
/L
Example 2.14
Convert pounds per day to milligrams per liter.
Quantity (lb/day)
Concentration(mg/L)
=
Volum
ee(MGD)
×
8.34 lb/MG/mg/L
Problem: The disinfection process uses 4820 pounds per day of chlorine to disinfect
a flow of 25.2 MGD. What is the concentration of chlorine applied to the effluent?
Solution:
Quantity (lb/day)
Volume (MGD)
Concentration
=
8.34 lb/MG/mg/L
4820 lb/day
25.2 MGD
×
=
= 22 .
mg/L
×
8.34 lb/MG/mg/L
Example 2.15
Convert pounds to flow in million gallons per day.
Quantity (lb/day)
Quantity (mg/L)
Flow (MGD)
=
× 8.34 lb/MG/mg/L
 
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