Water/Wastewater Laboratory Calculations - Basic Mathematics for Water and Wastewater Operators - page 257

Solution:

NV = NV

11 22

15 N × 1 0mL

0mL

= 0 4 . N × V

2

15 N 1

04

×

= V

2

. N

3 75 mL = V 2

■ Example 16.42
Problem: A 0.2- N solution is needed but a 2.7- N solution is on hand. How many mil-
liliters of the 2.7- N solution are needed to make 0.5 L of 0.2- N solution?

Solution:

NV = NV

11 22

27 . N × 50 0mL

0mL =

= 02 . N × V

2

27 . N 50

02

×

V

2

. N

6750 mL = V

2