Water/Wastewater Laboratory Calculations - Basic Mathematics for Water and Wastewater Operators - page 255

■ Example 16.35
Problem: If 260 mL of 3- N NaOH are diluted to 1000 mL, what is the new normality
of the solution?

Solution:

NV = NV

11 22

3 6 N × 0mL = N × 1 000 mL

2

3 6
1

N 0mL

000 mL
0.78

×

= N

2

= N

2

■ Example 16.36
Problem: If 600 mL of 10- N NaOH is diluted to 1 L, what is the new normality of
the solution?

Solution:

NV = NV

11 22

10 N × 60 0mL = N × 1 000 mL

2

10 N 0mL

0000mL

× 60

= N

2

1

6 = N

2

■ Example 16.37
Problem: Given 22 mL of 30- N HCl, how many milliliters of water should be added
to make 1.2- N HCL?

Solution:

NV = NV

11 22

30 N × 22 mL

mL

= 12 N × V

2

30 N × 22

= V

2

12 N

550 = V 2

■ Example 16.38
Problem: A 0.1- N solution is needed to conduct an analysis, but a 1.2- N solution is
on hand. How many milliliters of the 1.2- N solution are required to make 1 L of a
0.1- N solution?