Water Source and Storage Calculations - Basic Mathematics for Water and Wastewater Operators - page 230

For calculating lb/ac-ft copper sulfate, use the following equation to determine
the pounds of copper sulfate required (assume the desired copper sulfate dosage is
0.9 lb/ac-ft):

0.9 lb coppersulfate × c-ft a

Coppersulfate (lb) = (15.17)

1 ac-ft

■ Example 15.20
Problem: A pond has a volume of 35 ac-ft. If the desired copper sulfate dose is 0.9
lb/ac-ft, how many pounds of copper sulfate will be required?

Solution:

0.9 lb coppersulfate × c-ft a

Coppersulfate (lb) =

1 ac-ft

0.9 lb coppersulfate
1 ac-ft

= x lb coppersulfate
35 ac-ft

Then solve for x :

0.9 × 35 = x lb

x = 31.5 lb

The desired copper sulfate dosage may also be expressed in terms of lb/ac copper
sulfate. The following equation is used to determine the pounds of copper sulfate
required (assume that the desired copper sulfate dosage is 5.2 lb/ac):

5.2 lb coppersulfate × c a

Coppersulfate (lb) = (15.18)

1ac

■ Example 15.21
Problem: A small lake has a surface area of 6.0 ac. If the desired copper sulfate dose
is 5.2 lb/ac, how many pounds of copper sulfate are required?

Solution:

5.2 lb coppersulfate × 6 ac

Coppersulfate = = 31.2 lb

1a c