Environmental Engineering Reference
In-Depth Information
Example 15.10
Problem: The pumping water level for a well pump is 150 ft and the discharge pres-
sure measured at the pump discharge centerline is 3.5 psi. If the flow rate from the
pump is 700 gpm, use Equation 15.11 to calculate the water horsepower.
Solution: First calculate the field head. The discharge head must be converted from
psi to ft:
3.5 psi × 2.31 ft/psi = 8.1 ft
The field head, therefore, is
150 ft + 8.1 ft = 158.1 ft
The water horsepower can now be determined:
Fieldhead (ft)Capacity (gpm)
33,0
×
00 ft-lb/min
Water hp
=
158.1 ft
× ×
3,000 ft-lb/min
700 gpm
8.34 lb/gal
=
=
28 whp
3
Example 15.11
Problem: The pumping water level for a pump is 170 ft. The discharge pressure mea-
sured at the pump discharge head is 4.2 psi. If the pump flow rate is 800 gpm, use
Equation 5.11 to calculate the water horsepower.
Solution : The field head must first be determined. To determine field head, the dis-
charge head must be converted from psi to ft:
4.2 psi × 2.31 ft/psi = 9.7 ft
The field head can now be calculated:
170 ft + 9.7 ft = 179.7 ft
And the water horsepower can be calculated:
179.7 ft 800 gpm
3960
×
Water hp
=
=
36 whp
Example 15.12
Problem: A deep-well vertical turbine pump delivers 600 gpm. The lab head is 185
ft and the bowl efficiency is 84%. What is the bowl horsepower?
 
Search WWH ::




Custom Search