Environmental Engineering Reference
In-Depth Information
■
Example 11.11
Problem:
A sedimentation basin is 70 ft in diameter. What is the surface area of the
tank?
Solution:
Area = π ×
r
2
= 3.14 × (35 ft × 35 ft) = 3850 ft
2
Area = 0.785 ×
D
2
= 0.785 × (70 ft × 70 ft) = 3850 ft
2
■
Example 11.12
Problem:
A pipeline has a diameter of 14 in. What is the area of the pipe?
Solution:
Area = π ×
r
2
= 3.14 × (7 in. × 7 in.) = 154 in.
2
Area = 0.785 ×
D
2
= 0.785 × (14 in. × 14 in.) = 154 in.
2
VOLUME
Volume is the amount of space occupied by or contained in an object (see Figure
11.9). It is expressed in cubic units, such as cubic inches (in.
3
), cubic feet (ft
3
), or acre-
feet (1 acre-foot = 43,560 ft
3
).
v
oluMe
of
a
r
eCtangular
B
asin
The volume (
V
) of a rectangular object is obtained by multiplying the length by the
width by the depth or height:
V
=
L
×
W
×
H
(11.7)
where:
L
= Length.
W
= Width.
H
= Height (or depth).
W
L
D
FIGURE 11.9
Volu me.
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