Digital Signal Processing Reference
In-Depth Information
The linear model provides an initial output voltage and current of 1.250 V and
25mA when driving the 50- transmission line. Thus, the linear model is a clear
source of inaccuracy for modeling an interconnect system, although it may be
good enough for low-speed designs or for use in the early design stages of a
high-speed link.
We have two options at our disposal if a better match between design and
model is required. The first is to modify the transmitter design to give it a more
linear current-voltage relationship. This is most easily accomplished by placing a
resistive element in series with the output transistor. From Example 11-1 we note
that the transmitter actually conducts more than 95% of the maximum current by
the time the output swing has reached one-half of the maximum value (1.25 V).
As a result, the transmitter has an effective output impedance of approximately
25 across the output voltage range 0 to 1.25 V (the linear region of operation)
and a very high impedance from 1.25 to 2.5 V (the saturation region). By adding
a 25- resistor in series with the effective 25 of the transistor, we can better
approximate the desired 50- impedance, as shown in Figure 11-8.
Since it requires modifying the design, this approach is typically taken only
when a constant impedance over the entire voltage swing is critical to the design
[Esch and Chen, 2004]. An example is the AGP4X interface, which used a
series-terminated interconnect to transmit graphics data at 266Mb/s. The interface
relied on the transmitter to provide the termination, which required linearization
of the voltage-current relationship [Intel, 2002].
I D
50
V DS
W/L
=
222
I D
v GS
=
2.5 V
25 W
V DS
40
W/L
=
222
v GS
=
2.5 V
30
I D
50 W
V DS
20
10
0
0
0.5
1.0
1.5
2.0
2.5
V DS (V)
Figure 11-8 Comparison of push-pull transmitter current versus voltage characteristics
to a linear model.
 
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