Digital Signal Processing Reference
In-Depth Information
It is easy to see that the integral above will be positive as long as the square of
the reflection coefficient is less than or equal to 1 ( 2
1). This puts a limitation
on the termination resistance R t .
R t Z 0
R t + Z 0
2
2
=
1
The only condition where 2 > 1 is when R t is negative. Therefore, the system
is passive as long as R t
0.
8.2.3 Stability
A model of a passive component such as a transmission line, via, connector, or
package must remain stable in order to mimic real-world behavior successfully.
For the purposes of this topic, stability will be defined so that the output of
a system y ( t ) is stable for all bounded inputs x ( t ). Using this definition, the
stability of a linear time-invariant system is guaranteed only if all the elements
in the impulse response matrix [ h ( t )] satisfy [Triverio et al., 2007]
−∞ | h ij (t) |
dt<
(8-25)
Example 8-6 Determine the conditions of stability of a mass-spring system
similar to that used to derive the frequency dependence of the dielectric permit-
tivity in Section 6.3.2. Assume that the system is subjected to a sharp impulse
at time t = τ . The spring equation is given:
m d 2 x
dt 2
dt + kx
dx
+ b
= δ(t τ)
SOLUTION
Step 1: Solve the differential equation and compute the impulse response. For
simplicity sake, assume initially that m
2. Since the inverse
Laplace transform of the transfer function is the impulse response, it is easiest
to solve this problem by converting to the Laplace domain:
=
1, b
=
3, and k
=
s 2 Y(s) +
2 Y(s) = e τs
3 sY(s) +
= e τs . From equa-
where the Laplace transform of the input is L [ δ(t τ) ]
tion (8-9b), Y ( s ) is solved, where X(s) = e τs :
Y(ω) = H (ω)X(ω)
(8-9b)
Y(s) = H(s)e τs
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