Digital Signal Processing Reference
In-Depth Information
It is easy to see that the integral above will be positive as long as the square of
the reflection coefficient is less than or equal to 1 (
2
≤
1). This puts a limitation
on the termination resistance
R
t
.
R
t
−
Z
0
R
t
+
Z
0
2
2
=
≤
1
The only condition where
2
>
1 is when
R
t
is negative. Therefore, the system
is passive as long as
R
t
≥
0.
8.2.3 Stability
A model of a passive component such as a transmission line, via, connector, or
package must remain stable in order to mimic real-world behavior successfully.
For the purposes of this topic, stability will be defined so that the output of
a system
y
(
t
) is stable for all bounded inputs
x
(
t
). Using this definition, the
stability of a linear time-invariant system is guaranteed only if all the elements
in the impulse response matrix [
h
(
t
)] satisfy [Triverio et al., 2007]
∞
−∞
|
h
ij
(t)
|
dt<
∞
(8-25)
Example 8-6
Determine the conditions of stability of a mass-spring system
similar to that used to derive the frequency dependence of the dielectric permit-
tivity in Section 6.3.2. Assume that the system is subjected to a sharp impulse
at time
t
=
τ
. The spring equation is given:
m
d
2
x
dt
2
dt
+
kx
dx
+
b
=
δ(t
−
τ)
SOLUTION
Step 1:
Solve the differential equation and compute the impulse response. For
simplicity sake, assume initially that
m
2. Since the inverse
Laplace transform of the transfer function is the impulse response, it is easiest
to solve this problem by converting to the Laplace domain:
=
1,
b
=
3, and
k
=
s
2
Y(s)
+
2
Y(s)
=
e
−
τs
3
sY(s)
+
=
e
−
τs
. From equa-
where the Laplace transform of the input is
L
[
δ(t
−
τ)
]
tion (8-9b),
Y
(
s
) is solved, where
X(s)
=
e
−
τs
:
Y(ω)
=
H (ω)X(ω)
(8-9b)
Y(s)
=
H(s)e
−
τs
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