Digital Signal Processing Reference
In-Depth Information
Since the tangential component of the electric field must remain continuous, as
shown in equation (3-8), the electric field just outside the conductor surface can
be calculated with (5-40) evaluated at z =
0:
j) ωµ
2 σ
H ||
E || =
( 1
+
n
×
(5-41)
Section 3.2.1 says the electric field must terminate normal to a perfectly con-
ducting surface, however, equation (5-41) shows that for a good conductor, a
tangential component of E must exist just outside the conductor . Since (5-40)
describes the electric field decaying with increasing depth z into the surface, there
must be power flow into the conductor. The time-averaged value of the Poynting
vector described in Section 2.6.1 is used to calculate the power absorbed per unit
area:
= a z (E + ) 2
2 η
S ave
(2-121)
The intrinsic impedance (2-53) at the surface of the conductor, η s , is calculated
with (5-37) and (5-41):
+ j) ωµ
2 σ
E c
H c = ( 1
η s (z =
0 ) =
(5-42)
It is interesting to note that since µω/ 2 σ
1 /σ δ , (5-42) reduces to equation
(5-28), which is the series impedance of a transmission line:
=
+ j) ωµ
+ j) 1
σδ
( 1
2 σ = ( 1
Finally, the power flow per unit area into the conductor is calculated using
equation (2-121):
E c
2 2 σ 2
ωµσ
From (5-10), δ = 2 /ωµσ , yielding (5-43), which is the time-averaged power
absorbed by a flat conducting plane per unit area:
2 2 σ
ωµ =
2
4 σ H ||
4 σ H ||
ωµ
ωµ
S ave
=
=
2 η
ωµδ H ||
2
S ave
W / m 2
=
P plane
=
(5-43)
4
Equation (5-43) will allow for the solution of the resistive power losses of a good
conducting plane provided that the applied magnetic field
H || has been solved
for the idealized case of a perfect conducting plane.
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