Digital Signal Processing Reference
In-Depth Information
Since the tangential component of the electric field must remain continuous, as
shown in equation (3-8), the electric field just outside the conductor surface can
be calculated with (5-40) evaluated at
z
=
0:
j)
ωµ
2
σ
H
||
E
||
=
(
1
+
n
×
(5-41)
Section 3.2.1 says the electric field must terminate normal to a perfectly con-
ducting surface, however, equation (5-41) shows that
for a good conductor, a
tangential component of E must exist just outside the conductor
. Since (5-40)
describes the electric field decaying with increasing depth
z
into the surface, there
must be power flow into the conductor. The time-averaged value of the Poynting
vector described in Section 2.6.1 is used to calculate the power absorbed per unit
area:
=
a
z
(E
+
)
2
2
η
S
ave
(2-121)
The intrinsic impedance (2-53) at the surface of the conductor,
η
s
, is calculated
with (5-37) and (5-41):
+
j)
ωµ
2
σ
E
c
H
c
=
(
1
η
s
(z
=
0
)
=
(5-42)
It is interesting to note that since
√
µω/
2
σ
1
/σ δ
, (5-42) reduces to equation
(5-28), which is the series impedance of a transmission line:
=
+
j)
ωµ
+
j)
1
σδ
(
1
2
σ
=
(
1
Finally, the power flow per unit area into the conductor is calculated using
equation (2-121):
E
c
2
2
σ
2
ωµσ
From (5-10),
δ
=
√
2
/ωµσ
, yielding (5-43), which is the time-averaged power
absorbed by a flat conducting plane per unit area:
2
2
σ
ωµ
=
2
4
σ
H
||
4
σ
H
||
ωµ
ωµ
S
ave
=
=
2
η
ωµδ
H
||
2
S
ave
W
/
m
2
=
P
plane
=
(5-43)
4
Equation (5-43) will allow for the solution of the resistive power losses of a good
conducting plane provided that the applied magnetic field
H
||
has been solved
for the idealized case of a perfect conducting plane.
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