Digital Signal Processing Reference
In-Depth Information
Step 5: Calculate the ac resistance at 2 GHz using (5-17). Note that (5-18)
could be used as well.
πµ 0 f
σ
1
w +
1
6 h
R ac, micro
=
0 . 0117
1
=
( 3 mils )( 25 . 4
×
10 6 m/mil )
1
+
6 ( 2 mils )( 25 . 4
×
10 6 m/mil )
=
191 . 3 / m
=
4 . 86 / in.
Step 6: Calculate the internal inductance using (5-30).
R ac
ω =
4 . 86 / in.
2 π( 2
L internal
=
10 9 Hz ) =
0 . 387 nH/in.
×
Step 7: Calculate the total inductance using (5-20).
L total
= L internal
+ L external
=
8 . 03
+
0 . 387
=
8 . 42 nH / in.
5.2.4 Power Loss in a Smooth Conductor
In high-speed digital design, surface treatment of the copper foils used to con-
struct printed circuit boards (PCBs) significantly affects the power losses experi-
enced by a signal propagating on a transmission line. In this section, the power
losses of an electromagnetic wave impinging on a flat, smooth plane are exam-
ined. In later sections we explore the consequences of rough conductor surfaces.
First, we assume that the fields in the vicinity of a good but not perfect con-
ductor will behave approximately the same as for a perfect conductor. In Section
3.2.1 it was shown that the electric fields terminate normal to a perfect conduct-
ing surface and the magnetic fields are tangential to the surface. Furthermore, in
Section 5.1.2 it was shown that fields inside a conductor will attenuate exponen-
tially and are measured in terms of the skin depth δ . At high frequencies, the
boundary condition shown in (3-3) is true for a good conductor, except for a thin
transitional layer.
To derive an equation to predict the loss for a smooth plane, we first assume
that just outside the conductor there exists only a normal component of the
electric field ( E ) and a tangential component of the magnetic field ( H ), which
are the identical boundary conditions used for perfect conductors. Following
the approach outlined by Jackson [1999], Maxwell's equations are then used to
calculate the fields within the transition layer.
If a tangential H exists just outside the surface, the same H must exist just
inside the conductor surface. With the neglect of the displacement current, (2-33)
and (2-34) become
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