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269.0
269.5
NPEO Buoy Drift, 2002
270.0
270.5
271.0
V(t)=V 0 +A 0 e - ift
10*(1+i) km da - 1
V 0 =
-
271.5
A 0 =10 km da - 1
272.0
Fig. 2.2 Unmanned buoy trajectory from 26 to 29 September 2002. Plus symbols show satellite
navigation fixes every half an hour. The dashed curve shows the integral of the simple velocity
expression from theinitialposition at time270.0
Displacement from origin at 80.16
N, 164.50
W
265
10
264
5
0
Complex Demodulation,
offset 3 km east
263
−5
−10
GPS positions
−15
−20
262
-
15
-
10
-
5
0
5
10
15
20
25
km east
Fig. 2.3 Blackdotsshow GlobalPositioningSatellitenavigationfixesfortheSHEBAdriftstation
during a three-day period in September 1998. The dashed curve is position derived from complex
demodulation, offset 3km eastward for comparison
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