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where
=+
=−
a 22
a 23
14
26
A 11 =+
2
a 32
a 33
=−
=
a 21
a 23
24
46
A 12 =−
4
a 31
a 33
=+
=
a 21
a 23
21
42
A 13 =+
0
a 31
a 33
=−
=
a 22
a 23
13
26
A 21 =−
0
a 32
a 33
=+
=−
a 11
a 13
03
46
A 22 =+
12
a 31
a 33
=−
=
a 12
a 11
01
42
A 23 =−
4
a 31
a 32
=+
=
a 12
a 13
13
14
A 31 =+
1
a 22
a 23
=−
=
a 11
a 13
03
24
A 32 =−
6
a 21
a 23
=+
=−
a 11
a 12
01
21
A 33 =+
2
a 21
a 22
therefore, the cofactor matrix of A is
2
4
0
.
cofactor matrix of A
=
0
12
4
1
6
2
It can be shown that the product of a matrix with the transpose of its cofactor matrix
has the following form:
det A
0
...
0
0
det A
...
0
A ( cofactor matrix of A ) T
=
...
...
...
...
0
0
0
det A
and multiplying throughout by 1 / det A we have
( 1 / det A ) A ( cofactor matrix of A ) T
=
I
which implies that
( cofactor matrix of A ) T
det A
A 1
=
.
Naturally, this assumes that the inverse actually exists, and it will if det A
=
0.
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