Image Processing Reference
In-Depth Information
5.3 (Parseval-Plancherel) Conservation of the Scalar Product
We consider a scalar product between two members of our Hilbert space of periodic
functions, f = 2 T m F ( ω m ) ψ m and g = 2 T m G ( ω m ) ψ m :
= 2 π
T
2
F ( ω m ) ψ m ,
n
f, g
G ( ω n ) ψ n
m
= 2 π
T
2
F ( ω m ) G ( ω n )
ψ m n
mn
= 2 π
T
2
F ( ω m ) G ( ω n ) ( m
n )
mn
(2 π ) 2
T
F ( ω m ) G ( ω m )
=
(5.18)
m
To obtain Eq. (5.18), we changed the order of the summation and the integration (of
the scalar product). This is allowed for all functions f and g that are physically real-
izable. The δ ( m
n ) is the Kronecker delta whereby we obtained the last equality.
Notice that the Kronecker delta reduced the double sum to a single sum by replac-
ing n with m everywhere before it disappeared, a much appreciated behavior of δ
under summation. We explain the reason for this “sum-annihilating” property of the
Kronecker delta. Assume that we have written down all the terms one after the other,
F ( ω 1 ) G ( ω 1 ) δ (1 1) , F ( ω 1 ) G ( ω 2 ) δ (1 2) , F ( ω 1 ) G ( ω 3 ) δ (1 3) ···
(5.19)
The only terms that are nonzero are those when both indices are equal, n = m .
Accordingly, we can reach all terms that are nonzero in the sum by using a single
index in a single sum. Behaviorally, this is the same as saying that δ “replaces” one
of its indices in every other terms such that the argument of the δ becomes zero and
it “erases” the sum corresponding to the disappeared index, before vanishing itself.
The set of the discrete Fourier coefficients
{
F ( ω m )
} m =(
···
F ( ω 2 ) ,F ( ω 1 ) ,F ( ω 0 ) ,F ( ω 1 ) ,F ( ω 2 )
···
)
(5.20)
can be viewed as a vector with an infinite number of elements. Members constitute a
faithful and unique representation of f because of the synthesis formula, Eq. (5.14).
Can such infinite dimensional vectors be considered a Hilbert space on their own ac-
count? Yes, indeed. Scaling and addition are extended versions of their counterparts
in finite dimensional vector spaces:
(
···
αF ( ω 1 ) ,αF ( ω 0 ) ,αF ( ω 1 ) ,
···
)= α (
···
F ( ω 1 ) ,F ( ω 0 ) ,F ( ω 1 ) ,
···
)
(5.21)
and
( ···F ( ω 1 )+ G ( ω 1 ) ,F ( ω 0 )+ G ( ω 0 ) ,F ( ω 1 )+ G ( ω 1 ) , ··· )
=(
···
F ( ω 1 ) ,F ( ω 0 ) ,F ( ω 1 ) ,
···
)+(
···
G ( ω 1 ) ,G ( ω 0 ) ,G ( ω 1 ) ,
···
)
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