Image Processing Reference
In-Depth Information
B M =
{ ψ 1 ,
ψ 2 ,
···
,
ψ M }
(15.2)
yet to be specified, as
f 1 (1)
f 1 (2)
f 1 (3)
.
f 1 ( M )
f 2 (1)
f 2 (2)
f 2 (3)
.
f 2 ( M )
f k (1)
f k (2)
f k (3)
.
f k ( M )
f K (1)
f K (2)
f K (3)
.
f K ( M )
f 1 =
, f 2 =
,
···
, f k =
,
···
, f K =
,
(15.3)
where f k ( m ) is the m th component of the vector f k . Each vector f k can then be
written as
M
f k =
f k ( m )
ψ m
(15.4)
m =1
By using all M basis vectors, we can thus represent any of the observed f k without
error. This remains true even if we choose another basis set containing M orthogonal
vectors, as long as we include all M basis vectors in the expansion in Eq. (15.4).
Does the basis we choose really matter? Yes, it does, because in applications we
cannot always afford to choose complete bases of M vectors for a variety of reasons,
including that M can be too large. One must then expand each of the observed f k by
using fewer vectors:
N
f k =
f k ( m )
ψ m ,
where
N<M
(15.5)
m =1
Note that the only difference between Eq. (15.5) and Eq. (15.4) is in the number of
the terms in the summation, N and M , respectively. All terms in Eq. (15.5) exist in
Eq. (15.4), but not vice versa. The vectors
f 1 , f 2 ···
, f k ,
, f K
···
(15.6)
only approximate the corresponding observation, because the approximation error
f k
f k
(15.7)
is usually not zero.
Here, we are interested in finding an orthonormal (ON) basis,
B N :
B N = { ψ 1 , ··· , ψ N },
with
ψ i , ψ j = δ ij ,
(15.8)
that is “most economical” among all possible ON basis sets. Note that
B N is a “trun-
cated”
B M in that it has fewer basis vectors. Economical means that, despite the fact
that the basis
B N has fewer basis vectors than the full set, it should still represent
O
with a smaller basis truncation error ,
K
1
K
f k 2
f k
(15.9)
k
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