Direction in 2D - Vision with Direction - page 200

1
4 π 2

| ∇

| 2 d x I 11 = f (10.112)

and substituting k 2 min and k 2 max in Eq. (10.106) yields:
λ min = e ( k min )= 1

2 ( I 11 −|

I 20 | ) (10.113)

λ max = e ( k max )= 1

2 ( I 11 +

| I 20 | ) . (10.114)

That is:

| I 20 | = λ max − λ min (10.115)

arg I 20 =2 θ 0 (10.116)

I 11 = λ max + λ min (10.117)