Environmental Engineering Reference
In-Depth Information
This is called “below-cloud scavenging.” The rate of increase in concentration in the
droplet is given by the mass transfer to the drop (Seinfeld and Pandis, 2006):
D
P
6
d [A]
aq
d
t
= π
D
P
K
mt
[A]
g
,
π
d [A]
aq
d
t
6
D
P
K
mt
[A]
g
,
where we assume that the pollutant is irreversibly absorbed into the drop and the
pollutant is nonreactive. For a falling drop at its terminal velocity,
U
T
, we can write
d [A]
aq
d
t
=
d [A]
aq
d
z
=
U
T
since
U
T
=
d
z/
d
t
. Thus,
d [A]
aq
d
z
=
6
D
P
K
mt
U
T
[A]
g
.
If we assume that [A]
g
is constant (homogeneous atmosphere), we can obtain the
following equation upon integration:
K
mt
U
T
[A]
g
z
.
The mass scavenged (
W)
by a droplet of volume
π
D
P
/
6 will be given by ([A]
aq
-[A]
aq
)
times the droplet volume
6
D
P
[A]
aq
=
[A]
aq
+
W
=
π
D
P
K
mt
U
T
[A]
g
z
.
If the rainfall intensity is
R
I
(mm/h), the number of drops falling per unit area per hour
will be
N
d
m
2
/
h
K
mt
[A]
g
U
T
D
P
z
.
Hence, the rate of removal of the pollutant by rain (fog) drops from below-cloud volume
of
V
is given by
=
0.006
R
I
−
V
d [A]
g
d
t
=
N
d
WA
c
.
Noting that
V/A
c
=
z
,wehave
d [A]
g
d
t
=
0.006
R
I
K
mt
−
U
T
D
P
[A]
g
,
which upon integration gives
[A]
g
=
[A]
g
e
−λ
t
,
where
λ =
0.006
(R
I
K
mt
/U
T
D
P
)
iscalledthe
scavengingratio
.Theamountofpollutant
scavenged from the atmosphere by rain or fog depends on the drop diameter
D
P
. Note
that
λ
is inversely proportional to
D
P
; the smaller the drop diameter, the better the
scavenging efficiency. Small drops also have low
U
T
and hence have a large residence
time in the atmosphere, which increases the mass transfer to the drop.
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