Geology Reference
In-Depth Information
The boundary conditions for ™ arise immedi-
ately from those for T .Wehavethat™( z , t ) D 0for
t 0and™(0, t ) D 1for t > 0. Furthermore:
d 2
2 C d™
D 0
(12.34)
With respect to ǜ, the boundary conditions
assume the form:
lim
z !1
™. z ;t/ D 0 for any t>0
(12.29)
lim
ǜ!1
™.ǜ/ D 0 I ™.0/ D 1
(12.35)
A solution by similarity is based on the idea
that two solutions of ( 12.28 ) for different times
should have a “similar” spatial distribution of
temperatures. Therefore, z and t must appear in
a particular combination, just like solutions of
the plane wave equation require that distance
x and time t always appear in the combination
t - x / v , v being the wave velocity. In the case
of th e diffusion equation, the quantity L ( t ) D
p ›t represents a characteristic thermal diffusion
distance , thereby it is reasonable to assume that if
D ™( z , t ) is a solution to ( 12.28 ), then it wi ll be a
Now let us set:
d™
¥
(12.36)
Substituting into ( 12.34 ) reduces this equation
to a first-order differential equation:
C 2ǜ¥ D 0
(12.37)
function of the dimensionless ratio z = p ›t rather
than of an arbitrary combination of the variables
z and t . To simplify the results, it is convenient
to define a dimensionless similarity variable ǜ as
follows:
The solution is:
¥.ǜ/ D ae ǜ 2
(12.38)
Therefore, the general solution for ™ is:
z
2 p ›t
Z
ǜ. z ;t/
(12.30)
e 2 d C b
™.ǜ/ D a
(12.39)
0
Formally, the similarity implies that tempera-
ture distribution at time t can be obtained from the
distribution at time t 0 by stretching the distance z
by the square root of t 0 / t . In fact, the transfo rma -
Finally, substituting the boundary conditions
allows to express the solution to ( 12.34 )interms
of error function:
tion z ! z 0 D z p t 0 =t gives ǜ 0 D z 0 = 2 p ›t 0
D z = p t 0 =t= 2 p ›t 0
Z
ǜ
D z = 2 p ›t D ǜ.Now
let us rewrite the diffusion equation in terms of ǜ.
By the chain rule, we have:
2
p  
e 2 d 1 erf .ǜ/ D erfc .ǜ/
™.ǜ/ D 1
0
(12.40)
This solution can be easily converted into
@
@t D
d™
@t D
ǜ
2t
d™
(12.31)
a
temperature
distribution
using
( 12.27 )and
( 12.30 ). We have:
T. z ;t/ D .T 0 T i / erfc z
@
@ z D
d™
@ z D
1
2 p ›t
d™
(12.32)
2 p ›t
C T i
@ 2
@ z 2 D
d 2
2
d 2
2
1
2 p ›t
@ z D
1
4›t
(12.41)
(12.33)
Aplotof T vs z isshowninFig. 12.7 for
a sudden increase of the surface temperature
( T 0 > T i ). The near-surface region where the
Substituting into ( 12.28 ) gives the following
ordinary linear differential equation:
 
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