Geology Reference
In-Depth Information
Fig. 10.17
Stress drop
across a fault plane after an
earthquake.
T
s
and
T
0
s
are
the local fields of shear
stress along
S
before and
after slip
u
M
ij
D
M
0
n
i
b
u
i
This quantity is clearly:
u
j
C
n
j
b
(10.56)
Z
As we expected, this expression gives a sym-
metric tensor. Furthermore, it results:
T
s
.x;y/
C
T
s
.x;y/
dS (10.54)
1
S
T
s
D
S
Tr.M/
D
M
kk
D
2M
0
n
k
b
u
k
D
2M
0
.n
b
u
/
D
0
(10.57)
Now we note that T
s
S
represents the total surface
force exerted across the fault plane. Therefore,
the total energy release during an earthquake will
be given by:
Therefore, the trace of the moment tensor is
always zero. The expression (
10.56
)showsthat
the moment tensor can be separated into a scalar
strength, corresponding to the seismic moment
M
0
, and a kinematic component associated with
the tensor quantity m
ij
n
i
b
T
s
M
0
E
D
T
s
S
u
D
(10.55)
u
i
. The latter
can be rewritten to make explicit the relation
between the components of
M
and the focal
mechanism. In fact, the components of the versor
n
depend from both the fault strike, ¥, and the dip,
•, while
u
j
C
n
j
b
The stress drop associated with large earth-
quakes is generally estimated from the seismic
moment. In the case of shallow events, it varies
between 1 and 10 MPa. Often earthquakes along
plate boundaries have lower stress drops than
intraplate events (Shearer
2009
and references
therein). It is estimated that the average •
T
s
is
3 MPa in the case of plate boundary earth-
quakes and
6 MPa for intraplate events. This
is possibly a consequence of a lower area of
intraplate faults with respect to the typical dimen-
sions of plate boundary faults.
The scalar seismic moment measures the
strength of an earthquake. Therefore, it is quite
intuitive that it must be related to the moment
tensor components
M
ij
. In fact, it is possible to
show (e.g., Udías
1999
)thatif
n
is the versor
normal to a fault plane and
u
depends from the rake œ. Therefore, it
is easy to prove that the components of
M
in a
local reference frame oriented as
x
N,
y
E,
z
Down are given by:
8
<
b
M
11
D
M
0
.sin • cosœ sin 2¥
C
sin 2• sin œsin
2
¥
M
12
DC
M
0
.sin • cos œ cos2¥
C
0:5 sin 2• sin œ sin 2¥/
M
13
D
M
0
.cos• cos œ cos¥
C
cos 2• sin œ sin
¥
/
M
22
DC
M
0
.sin • cos œ sin 2¥
(10.58)
:
sin 2• sin œcos
2
¥
M
23
D
M
0
.cos• cos œ sin ¥
cos2• sin œ cos¥/
M
33
DC
M
0
sin 2• sin œ
b
u
is the seismic
slip versor, so that
u
D
0, then an analytic
expression for the moment tensor is:
n
b