Biology Reference
In-Depth Information
In this case,
X
2
SSR
ð
r
;
c
Þ¼
1 ½
Y i
G
ð
r
;
c
X i Þ
:
(8-33)
;
i
¼
We begin with initial guesses r
c 0 and the Taylor
approximation from Eq. (8-17) for the values r
¼
r 0 and c
¼
¼
r 0 and c
¼
c 0 :
Þþ @
G
ð
r 0
;
c 0
;
X i
Þ
Þþ @
G
ð
r 0
;
c 0
;
X i
Þ
G
ð
r
;
c
X i
Þ
G
ð
r 0
;
c 0
X i
ð
r
r 0
ð
c
c 0
Þ:
;
;
@
r
@
c
(8-34)
Because for the least-squares values of r and c, we want
Y i ¼
G
ð
r
;
c
X i Þþ
experimental uncertainties
;
;
the equations used to find those values are
X i Þþ @
G
ð
r 0
;
c 0
;
X i
Þ
r 0 Þþ @
G
ð
r 0
;
c 0
;
X i
Þ
Y i ¼
G
ð
r 0 ;
c 0 ;
ð
r
ð
c
c 0 Þ:
@
r
@
c
As in the one-parameter case, we have one equation of this form for
every experimental data point (X i ,Y i ) and can express this set of
equations more conveniently in matrix notation as P
e ¼
Y*, where
2
4
3
5
@
G
ð
r 0 ;
c 0 ;
X 1 Þ
@
G
ð
r 0 ;
c 0 ;
X 1 Þ
@
r
@
c
2
4
3
5 ;
@
G
ð
r 0 ;
c 0 ;
X 2 Þ
@
G
ð
r 0 ;
c 0 ;
X 2 Þ
Y 1
G
ð
r 0 ;
c 0 ;
X 1 Þ
Y 2
G
ð
r 0 ;
c 0 ;
X 2 Þ
@
r
@
c
Y ¼
P
¼
;
and
.
.
.
Y n
G
ð
r 0 ;
c 0 ;
X n Þ
@
G
ð
r 0 ;
c 0 ;
X n Þ
@
G
ð
r 0 ;
c 0 ;
X n Þ
@
r
@
c
r
r 0
e ¼
:
c
c 0
The solution
can be obtained as in Eq. (8-31), with the iterative process
continuing until
e
e þ
guess
)
better guess returns
e ¼
0.
E XERCISE 8-4
Demonstrate that the values for parameters r and c obtained from the
Gauss-Newton method are the least-squares estimates for r and c by
showing these values provide a minimum for the SSR from Eq. (8-33).
Hint: Show that the values obtained for r and c are such that
@
SSR
ð
r
;
c
Þ
@
SSR
ð
r
;
c
Þ
¼
0
and
¼
0
:
@
r
@
c
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