Biology Reference
In-Depth Information
In this case,
X
2
SSR
ð
r
;
c
Þ¼
1
½
Y
i
G
ð
r
;
c
X
i
Þ
:
(8-33)
;
i
¼
We begin with initial guesses r
c
0
and the Taylor
approximation from Eq. (8-17) for the values r
¼
r
0
and c
¼
¼
r
0
and c
¼
c
0
:
Þþ
@
G
ð
r
0
;
c
0
;
X
i
Þ
Þþ
@
G
ð
r
0
;
c
0
;
X
i
Þ
G
ð
r
;
c
X
i
Þ
G
ð
r
0
;
c
0
X
i
ð
r
r
0
ð
c
c
0
Þ:
;
;
@
r
@
c
(8-34)
Because for the least-squares values of r and c, we want
Y
i
¼
G
ð
r
;
c
X
i
Þþ
experimental uncertainties
;
;
the equations used to find those values are
X
i
Þþ
@
G
ð
r
0
;
c
0
;
X
i
Þ
r
0
Þþ
@
G
ð
r
0
;
c
0
;
X
i
Þ
Y
i
¼
G
ð
r
0
;
c
0
;
ð
r
ð
c
c
0
Þ:
@
r
@
c
As in the one-parameter case, we have one equation of this form for
every experimental data point (X
i
,Y
i
) and can express this set of
equations more conveniently in matrix notation as P
e ¼
Y*, where
2
4
3
5
@
G
ð
r
0
;
c
0
;
X
1
Þ
@
G
ð
r
0
;
c
0
;
X
1
Þ
@
r
@
c
2
4
3
5
;
@
G
ð
r
0
;
c
0
;
X
2
Þ
@
G
ð
r
0
;
c
0
;
X
2
Þ
Y
1
G
ð
r
0
;
c
0
;
X
1
Þ
Y
2
G
ð
r
0
;
c
0
;
X
2
Þ
@
r
@
c
Y
¼
P
¼
;
and
.
.
.
Y
n
G
ð
r
0
;
c
0
;
X
n
Þ
@
G
ð
r
0
;
c
0
;
X
n
Þ
@
G
ð
r
0
;
c
0
;
X
n
Þ
@
r
@
c
r
r
0
e ¼
:
c
c
0
The solution
can be obtained as in Eq. (8-31), with the iterative process
continuing until
e
e þ
guess
)
better guess returns
e ¼
0.
E
XERCISE
8-4
Demonstrate that the values for parameters r and c obtained from the
Gauss-Newton method are the least-squares estimates for r and c by
showing these values provide a minimum for the SSR from Eq. (8-33).
Hint: Show that the values obtained for r and c are such that
@
SSR
ð
r
;
c
Þ
@
SSR
ð
r
;
c
Þ
¼
0
and
¼
0
:
@
r
@
c