Biology Reference
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q 0 by the time of reproduction. Thus, the number of A alleles at that
time will be 2p 0 N
to N
a
þ
2p 0 q 0 N, and the number of a alleles will be
q 0 N
2
2p 0 q 0 N. Denoting the proportions of the A and a alleles in the
first generation by p 1 and q 1 , we now calculate that:
a
þ
q 0 N
2
þ
2p 0 q 0 N
a
q 1
¼
q 0 N
2p 0 N
2
þ
2p 0 q 0 N
þ
þ
2p 0 q 0 N
a
0
1
(3-5)
q 0 þ
p 0 q 0
q 0 þ
p 0
a
a
@
A :
¼
p 0 ¼
q 0
q 0 þ
q 0 þ
p 0
2p 0 q 0 þ
2p 0 q 0 þ
a
a
The proportion p 1 could be calculated similarly, but we assumed that
A and a are the only alleles present in the population, so it is easier to
state that p 1 ¼
q 1 . Similarly, if p n and q n denote the proportions of the
A and a alleles in the nth generation, then because of weaker fitness
of the aa genotype, these frequencies will change in the (n
1
þ
1)-st
generation to:
q n þ 1
q n þ
p n
a
¼
q n
and p n þ 1
¼
1
q n þ 1
:
(3-6)
a
q n þ
2p n q n
þ
p n
Notice how different this situation is compared with the Hardy-
Weinberg case discussed previously. The allelic frequencies of A and
a now change from generation to generation, and, when we know the
frequencies for any given generation, Eq. (3-6) allows us to compute
their values for the following generation. Formulas such as
Eq. (3-6) are called recursive formulas.
Notice that because:
q n þ
p n ¼ð a
2p n q n
þ
q n
þ
p n
Þ
q n
þ
p n
ð
q n
þ
p n
Þ¼ð a
q n
þ
p n
Þ
q n
þ
p n
;
a
Eq. (3-6) could be rewritten as:
q n þ
p n
a
q n þ 1 ¼
q n
p n :
(3-7)
ð a
q n þ
p n Þ
q n þ
Now, because
< 1
; a
p n <p n and because p n ¼
1
q n , we have
a
a ð
1
q n Þ
<p n ;
which is the same as
<
q n þ
p n . This implies that
a
a
a
q n
þ
p n
< 1 and, together with Eq. (3-7), proves that q n þ 1 <q n .
ð a
q n þ
p n Þ
q n þ
p n
Thus, the allelic frequency of the harmful allele a does indeed decrease
from generation to generation.
Our next goal is to establish what happens to the harmful allele a in the
long run. Will it disappear from the gene pool or stabilize at a nonzero
value? More importantly, are we sure the limit for the sequence q 0 , q 1 ,
q 2 ,
, q n ,
exists?
...
...
The last question has an easy answer. Because the sequence q 0 ,q 1 ,q 2 ,
,
...
q n ,
is a decreasing sequence of numbers bounded below by 0, the
...
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