Environmental Engineering Reference
In-Depth Information
Substituting Eq. (6.158) into the equation of PDS (6.157) and using Eq. (6.159a)
yields
u
t
τ
0
+
B
2
∂
∂
A
2
u
tt
−
Δ
u
−
t
Δ
u
1
W
ϕ
+
∂
t
2
1
W
ϕ
2
1
τ
0
∂
∂
τ
0
+
∂
τ
0
+
∂
B
2
B
2
=
t
−
Δ
t
−
Δ
t
∂
∂
∂
1
W
ϕ
−
1
W
ϕ
τ
0
+
∂
B
2
∂
∂
τ
0
+
∂
A
2
B
2
B
2
−
Δ
t
−
Δ
t
Δ
t
−
Δ
∂
∂
1
2
W
ϕ
∂
1
τ
0
τ
0
∂
W
ϕ
∂
t
+
∂
B
2
∂
∂
A
2
=
−
Δ
W
ϕ
−
t
Δ
W
ϕ
t
2
1
2
W
ϕ
∂
+
∂
∂
τ
0
∂
W
ϕ
∂
t
+
∂
B
2
∂
∂
A
2
−
Δ
W
ϕ
−
t
Δ
W
ϕ
t
2
t
1
2
W
ϕ
∂
τ
0
∂
W
ϕ
∂
t
+
∂
B
2
∂
∂
B
2
A
2
−
Δ
−
Δ
W
ϕ
−
t
Δ
W
ϕ
=
0
.
t
2
Therefore, the
u
in Eq. (6.158) satisfies the equation of PDS (6.157).
By Eq. (6.159b), we have
(
M
,
t
)
1
W
ϕ
t
=
0
τ
0
+
∂
B
2
u
(
M
,
0
)=
t
−
Δ
∂
t
=
0
−
W
ϕ
t
=
0
=
ϕ
(
1
τ
)+
∂
W
ϕ
∂
B
2
=
W
ϕ
(
M
,
0
Δ
M
)
t
0
and
1
W
ϕ
(
∂
u
t
=
∂
τ
0
+
∂
B
2
t
−
Δ
M
,
t
)
∂
∂
t
∂
2
W
ϕ
∂
τ
0
∂
1
W
ϕ
∂
t
+
∂
B
2
∂
∂
A
2
=
−
t
Δ
W
ϕ
=
Δ
W
ϕ
,
t
2
such that
t
=
0
=
W
ϕ
t
=
0
=
∂
u
A
2
Δ
0
.
∂
t
in Eq. (6.158) also satisfies the two initial conditions of
PDS (6.157), thus verifying that it is the solution of Eq. (6.157).
Therefore, the
u
(
M
,
t
)
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