Environmental Engineering Reference
In-Depth Information
Substituting Eq. (6.158) into the equation of PDS (6.157) and using Eq. (6.159a)
yields
u t
τ 0 +
B 2
A 2
u tt
Δ
u
t Δ
u
1
W ϕ +
t 2 1
W ϕ
2
1
τ 0
τ 0 +
τ 0 +
B 2
B 2
=
t
Δ
t
Δ
t
1
W ϕ
1
W ϕ
τ 0 +
B 2
τ 0 +
A 2
B 2
B 2
Δ
t
Δ
t Δ
t
Δ
1
2 W ϕ
1
τ 0
τ 0
W ϕ
t +
B 2
A 2
=
Δ
W ϕ
t Δ
W ϕ
t 2
1
2 W ϕ
+
τ 0
W ϕ
t +
B 2
A 2
Δ
W ϕ
t Δ
W ϕ
t 2
t
1
2 W ϕ
τ 0
W ϕ
t +
B 2
B 2
A 2
Δ
Δ
W ϕ
t Δ
W ϕ
=
0
.
t 2
Therefore, the u
in Eq. (6.158) satisfies the equation of PDS (6.157).
By Eq. (6.159b), we have
(
M
,
t
)
1
W ϕ
t = 0
τ 0 +
B 2
u
(
M
,
0
)=
t
Δ
t = 0
W ϕ t = 0 = ϕ (
1
τ
)+
W ϕ
B 2
=
W ϕ (
M
,
0
Δ
M
)
t
0
and
1
W ϕ (
u
t =
τ 0 +
B 2
t
Δ
M
,
t
)
t
2 W ϕ
τ 0
1
W ϕ
t +
B 2
A 2
=
t Δ
W ϕ =
Δ
W ϕ ,
t 2
such that
t = 0 =
W ϕ t = 0 =
u
A 2
Δ
0
.
t
in Eq. (6.158) also satisfies the two initial conditions of
PDS (6.157), thus verifying that it is the solution of Eq. (6.157).
Therefore, the u
(
M
,
t
)
 
Search WWH ::




Custom Search